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Gemiola [76]
1 year ago
13

A brightfield microscope equipped with a ____________ ___________ stop is able to block light from the illuminator creating brig

ht objects on a dark background.
Physics
1 answer:
Arturiano [62]1 year ago
4 0

Answer: A Brightfield microscope equipped with an opaque light stop is able to block light from the illuminator and creating bright objects on a dark background.

Explanation: To find the correct statement about Brightfield microscope, we need to know more about the Brightfield microscope.

<h3>what is Brightfield microscope?</h3>
  • The Brightfield microscopic technique is generally used with the compound microscopes and, these are one, among the widely used optical illumination techniques.
  • The Brightfield microscope or Compound light microscope is an optical instrument, which uses light rays and produces dark images with a bright background.
<h3>How Bright field microscope works?</h3>
  • A brightfield microscope equipped with a opaque light stop, will produce bright objects on a dark background by blocking the light illuminated from the light source.
  • This opaque light stop, blocks the light rays that arising from the illuminator to the objective lenses and, only allows the reflected or transmitted light of the specimen. As a result, we get bright objects with a dark background.

Thus, we can conclude that, A Brightfield microscope equipped with an opaque light stop is able to block light from the illuminator and creating bright objects on a dark background.

Learn more about the Brightfield microscope here: brainly.com/question/28019837

#SPJ4

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Answer:

Wavelength = 736.67 nm

Explanation:

Given

Energy of the photon = 2.70 × 10⁻¹⁹ J

Considering:

Energy=h\times frequency

where, h is Plank's constant having value as 6.63 x 10⁻³⁴ J.s

The relation between frequency and wavelength is shown below as:

c = frequency × Wavelength

Where, c is the speed of light having value = 3×10⁸ m/s

So, Frequency is:

Frequency = c / Wavelength

So,  Formula for energy:

Energy=h\times \frac {c}{\lambda}

Energy = 2.70 × 10⁻¹⁹ J

c = 3×10⁸ m/s

h = 6.63 x 10⁻³⁴ J.s

Thus, applying in the formula:

2.70\times 10^{-19}=6.63\times 10^{-34}\times \frac {3\times 10^8}{\lambda}

Wavelength = 736.67 × 10⁻⁹ m

1 nm = 10⁻⁹ m

So,

<u>Wavelength = 736.67 nm</u>

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