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Gemiola [76]
2 years ago
13

A brightfield microscope equipped with a ____________ ___________ stop is able to block light from the illuminator creating brig

ht objects on a dark background.
Physics
1 answer:
Arturiano [62]2 years ago
4 0

Answer: A Brightfield microscope equipped with an opaque light stop is able to block light from the illuminator and creating bright objects on a dark background.

Explanation: To find the correct statement about Brightfield microscope, we need to know more about the Brightfield microscope.

<h3>what is Brightfield microscope?</h3>
  • The Brightfield microscopic technique is generally used with the compound microscopes and, these are one, among the widely used optical illumination techniques.
  • The Brightfield microscope or Compound light microscope is an optical instrument, which uses light rays and produces dark images with a bright background.
<h3>How Bright field microscope works?</h3>
  • A brightfield microscope equipped with a opaque light stop, will produce bright objects on a dark background by blocking the light illuminated from the light source.
  • This opaque light stop, blocks the light rays that arising from the illuminator to the objective lenses and, only allows the reflected or transmitted light of the specimen. As a result, we get bright objects with a dark background.

Thus, we can conclude that, A Brightfield microscope equipped with an opaque light stop is able to block light from the illuminator and creating bright objects on a dark background.

Learn more about the Brightfield microscope here: brainly.com/question/28019837

#SPJ4

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Answer:

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6 0
4 years ago
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Find the angle formed by two forces of 7N and 15N respectively if its result is worth 20N
nadezda [96]
First, you need to make certain assumptions before solving this question. Why? Because there are no information given about the direction of these forces. In such questions as above, ALWAYS make the following assumptions:

1) Take first force, say F_{1}, and assume that it is pointing towards the x-direction.

Let us take the 7N force! By keeping the above assumption in our minds, the force vector would be like:
F_{1} = 7i, where i = Unit vector in the x-direction.

2) Take the second force, say F_{2}, and assume that it is making an angle \alpha with the first force F_{1}.

Let us take the 15N force! By keeping the above assumption in our minds, the forces vector would be like:

F_{2} = (15*cos \alpha)i + (15*sin \alpha )j

Now from simple vector addition, we know that,
F_{R} = F_{1} + F_{2} --- (A)

Where F_{R} = Resultant vector.
NOTE: In equation (A), all forces are in vector notation. Assume that there is an arrow head on top of them.

Let us find F_{1}+F_{2} first!
F_{1}+F_{2} =  7i+(15*cos \alpha)i + (15*sin \alpha )j

=> F_{1}+F_{2} =  (7+15*cos \alpha)i + (15*sin \alpha )j

Now the magnitude of F_{1}+F_{2} is,
| F_{1}+F_{2}| = \sqrt{ (7+ 15*cos \alpha)^{2} +  (15*sin \alpha )^{2}}

=> | F_{1}+F_{2}| = \sqrt{ 49 + 225*(cos \alpha)^{2} + 210*(cos \alpha)+ 255*(sin \alpha )^{2}}

Since (sin \alpha)^{2} + (cos \alpha)^{2} = 1, therefore,

=> | F_{1}+F_{2}| = \sqrt{ 49 + 225 + 210*(cos \alpha)}

Since  | F_{1}+F_{2}| = |F_{R}|, and the magnitude of the resultant force is 20N, therefore,

 |F_{R}| = | F_{1}+F_{2}|
20 = \sqrt{ 49 + 225 + 210*(cos \alpha)}

Take square on both sides,
400 = 49 + 225 + 210*(cos \alpha)
(cos \alpha) =  \frac{3}{5}

\alpha = 53.13^{o}

Ans: Angle formed by the two forces, 7N and 15N, is: 53.13°

-israr

4 0
3 years ago
Static Friction
kkurt [141]
Name the element and explain why it is unusual:
a)A liquid metal
b)A non-metal that conducts electricity
3 0
3 years ago
A block of mass 22 kg is sliding along the ice at constant speed 5.0 m/s just ahead of it is q block of mass 29 kg sliding in th
mars1129 [50]

Answer:

Answer:

New speed of the 22-kg block is 1.57 m/s

Explanation:

Mass of block  

Mass of another block  

Initial speed of the block  

Initial speed  of the another block  

Initial speed  of the another block  

For conservation of momentum, we have

Substitute all the values and solving for final speed of the 22kg block is

new speed of the 22-kg block is 1.57 m/s

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3 years ago
An electromagnetic wave has a frequency of 4.0 x 1018 Hz. What is the
trapecia [35]

Answer: D

Wavelength λ = 7.5 × 10^-11 m

Explanation:

You are given the frequency of an electromagnetic wave to be:

F = 4.0 x 1018 Hz. And the speed of light C to be

C = 3 × 10^8 m/s

From wave speed formula:

Wave speed is the product of waves frequency and wavelength. That is,

V = fλ

Where

f = frequency

λ = wavelength

V = C = speed of light

Substitute the values of the parameters into the formula

C = fλ

3 × 10^8 = 4 × 10^18 × λ

Make λ the subject of formula

λ = (3×10^8)/(4×10^18)

λ = 7.5 × 10^-11 m

Therefore, the wavelength of the wave is 7.5 × 10^-11 m

8 0
3 years ago
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