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aalyn [17]
3 years ago
10

calculate the acceleration of a 520 kg car that had 5050N of net force exerted on it by the engine. explain how you solve the pr

oblem please
Physics
1 answer:
elena55 [62]3 years ago
3 0

I'll explain first:

You use the formula for Newton's second law of motion.
The formula is so simple, and it solves so many problems,
that it's actually a good idea to memorize it.
(I learned it 58 years ago, and I still remember it.)

The formula is                 F  =  M A

It means                    Force = (mass) x (acceleration)

In this question, you know the force, and you know the mass,
so calculating the acceleration is a piece-o-cake.

                                                     Force = (mass) x (acceleration)

                                                (5,050 N) = (520 kg) x (acceleration)

Divide each side by  520 kg :  (5,050 N / 520 kg) = acceleration

                                                 Acceleration = 9.712 m/s² (rounded)
 
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When three people with a total mass of 2.00 x 102 kg step into their 1.200 x 103 kg car, the car’s
Aleksandr-060686 [28]

Answer:

a

 k =  457333.3 N/m

b

x_a  =0.09\ m      

Explanation:

From the question we are told that

    The total mass of  three people is  M  = 2.00*10^{2} \ kg

     The mass of the car is  m_c  =  1.200 *10^{3} \ kg

     The compression of the car spring is  x = 3 \ cm  = 0.03 \ m

     

Generally the spring constant is mathematically represented as

          k =  \frac{F}{x}

Here F is the force exerted by the mass of three people and that of the car , this is mathematically represented as        

=>       F = (M +m_c) *g

=>       F = ([2.0*10^{2} ]+[ 1.200*10^{3}]) * 9.8

=>       F = 13720 \  N

So

        k =  \frac{13720}{0.03}

=>     k =  457333.3 N/m

Generally if the mass which the car is loaded with is  m  =  3.00*10^{2} \ kg

Then the force experienced by the spring is  

         =>       F_a = (m +m_c) *g

         =>       F_a = (3.00*10^{3} + 1.200 *10^{3}) * 9.8

         =>       F_a = 41160 \  N

Generally from the above formula the compression is  

       x_a  = \frac{F_a}{k}

=>    x_a  = \frac{41160}{457333.3}

=>    x_a  =0.09\ m      

3 0
3 years ago
The resultant of two forces acting on the same point simultaneously will be the greatest when the angle between them is:a) 180 d
r-ruslan [8.4K]

Answer:

0 degrees

Explanation:

Let F_1\ and\ F_2 are two forces. The resultant of two forces acting on the same point is given by :

F_R=\sqrt{F_1^2+F_2^2+2F_1F_2\ cos\theta}

Where \theta is the angle between two forces

When \theta=0 i.e. when two forces are parallel to each other,

F_R=\sqrt{F_1^2+F_2^2+2F_1F_2\ cos(0)}

F_R=\sqrt{F_1^2+F_2^2+2F_1F_2}

When \theta=90^{\circ} i.e. when two forces are parallel to each other,

F_R=\sqrt{F_1^2+F_2^2+F_1F_2\ cos(90)}

F_R=\sqrt{F_1^2+F_2^2}

When \theta=180^{\circ} i.e. when two forces are parallel to each other,

F_R=\sqrt{F_1^2+F_2^2+F_1F_2\ cos(180)}

F_R=\sqrt{F_1^2+F_2^2-2F_1F_2}

It is clear that the resultant of two forces acting on the same point simultaneously will be the greatest when the angle between them is 0 degrees. Hence, this is the required solution.

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Answer:

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sin ( 90 - 25 ) / sin( 90 - C)  = μ

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From these equations

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C= 56°

sinC = 1.33 / μ

μ = 1.33 / sinC

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