U = 0, the initial vertical velocity
Assume g = 9.8 m/s² and ignore air resistance.
Use the formula
v = u + gt
where v = vertical velocity after t seconds.
That is,
v = 0 + (9.8 m/s²)*(10 s) = 98.0 m/s
Answer: 98.0 m/s
Answer:
The friction force and the x component for the weight should be the reaction forces that are opposite and equal to the action force, which causes the locomotive to move up the hill if the velocity of the locomotive remains constant.
Explanation:
<u>When the locomotive starts to pull the train up, appears two reaction forces opposed to the action force in the direction of the move. </u>
The first one is due to the friction between the wheels and the ground, it will be the friction force (Fr):
Fr = μ*Pₓ =μmg*sin(φ)
<em>where μ: friction dynamic coefficient, Pₓ: is the weight component in the x-axis, m: total mass = train's mass + locomotive's mass, g: gravity, and sin(φ): is the angle respect to the x-axis.</em>
And the second one is the x component for the weight (Wₓ):
Wₓ = mg*cos(φ)
<em>where cos(φ): is the angle respect to the y-axis. </em>
<em> </em>
These two forces should be the same as the action force, which causes the locomotive to move up the hill if the velocity of the locomotive remains constant.
Answer:
B. Atoms are altered in both processes
Explanation:
The answer to the question is 150 meters
