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Alik [6]
1 year ago
6

What volume is occupied by 0.102 molmol of helium gas at a pressure of 0.95 atmatm and a temperature of 305 kk ?

Chemistry
1 answer:
zalisa [80]1 year ago
8 0

The volume occupied by 0.102 mole of the helium gas is 2.69 L

<h3>Data obtained from the question</h3>

The following data were obtained from the question:

  • Number of mole (n) = 0.102 moles
  • Pressure (P) = 0.95 atm
  • Temperature (T) = 305 K
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Volume (V) =?

<h3>How to determine the volume </h3>

The volume of the gas can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

Divide both sides by P

V = nRT / P

V = (0.102 × 0.0821 × 305) / 0.95

V = 2.69 L

Thus, the volume of the gas is 2.69 L

Learn more about ideal gas equation:

brainly.com/question/4147359

#SPJ1

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A pizza is an example of a heterogeneous mixture. Explain why it is classified as such?​
My name is Ann [436]

Answer:

Hi!

So, a homogeneous mixture is when the parts that make up the mixture are all mixed in perfectly evenly, so they're only appearing as one uniform substance.

In a heterogeneous mixture, the pieces are not evenly mixed. A pizza has separate parts, like the crust and toppings, so it's a heterogeneous mixture.    

6 0
4 years ago
Read 2 more answers
the osmotic pressure ofa solution containing 5.87 mg of an unknown protein per 10ml of solution is 2.45 torr at 25 degree celsiu
Neko [114]

Answer: The molar mass of the unknown protein is 4.45\times 10^9g/mol

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

\pi=iMRT

Or,

\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT

where,

\pi = osmotic pressure of the solution = 2.45 torr

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (protein) = 5.87 mg = 5870 g   (Conversion factor: 1 g = 1000 mg)

Volume of solution = 10 mL

R = Gas constant = 62.364\text{ L.torr }mol^{-1}K^{-1}

T = temperature of the solution = 25^oC=[273+25]=298K

Putting values in above equation, we get:

2.45torr=1\times \frac{5870\times 1000}{\text{Molar mass of protein}\times 10}\times 62.364\text{ L.torr}mol^{-1}K^{-1}\times 298K\\\\\text{molar mass of protein}=4.45\times 10^9g/mol

Hence, the molar mass of the protein is 4.45\times 10^9g/mol

4 0
3 years ago
An aluminum can has a height of 4.83 inches, a diameter of 2.60 inches, and a uniform wall/end thickness of 0.0112 inches. If th
Triss [41]
Strategy: with the measures you can determine the volume of the plate of aluminum. Then you can use the density of aluminum to calculate the mass.

With the mass of aluminum and its atomic mass you can find the number of moles and thereafter the number of atoms.

Finally divide the cost by the number of atoms to find the cost of one single atom.

Let's do it.

Volume of aluminum plate, V: 0.0112 in* 4.83 in* 2.60 in * [2.54 cm/in]^3 = 2.305 cm^3

Density of aluminum (from Wikipedia), d = 2.70 g/cm^3

mass, m = d*V = 2.305 cm^3 * 2.70 g/ cm^3 = 6.22 g

Atomic mass of aluminum (from Wikipedia), am = 27 g / mol

Number of moles, n = m/am = 6.22 g / 27 g / mol =   0.23 mol

Number of atoms = n*Avogadro constant = 0.23 mol * 6.022 * 10^23 atoms/mol = 1.39*10^23

Cost per atom = cost of the can / number of atoms =$ 0.05 /1.39*10^23 atoms  =  3.60 * 10^ - 25 $/atom
4 0
3 years ago
How many atoms is in a molecule of omega 3 fatty acid
Nastasia [14]

Answer:

There are 18 carbon atoms in a molecule of omega 3 fatty acid

Explanation:

3 0
3 years ago
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C + O2 → CO2 ,
DerKrebs [107]
First, if you want to get the amount of production from the equation, you need to use the units of mol. So, we need to know the molar mass of C which is 15.75/12=1.31 mol. Then we need to use the less part(O2) to get the production amount which is 0.116 mol. Then we can get the answer in units of g: 0.116*(12+16*2)=5.104 g.
5 0
4 years ago
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