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Alik [6]
1 year ago
6

What volume is occupied by 0.102 molmol of helium gas at a pressure of 0.95 atmatm and a temperature of 305 kk ?

Chemistry
1 answer:
zalisa [80]1 year ago
8 0

The volume occupied by 0.102 mole of the helium gas is 2.69 L

<h3>Data obtained from the question</h3>

The following data were obtained from the question:

  • Number of mole (n) = 0.102 moles
  • Pressure (P) = 0.95 atm
  • Temperature (T) = 305 K
  • Gas constant (R) = 0.0821 atm.L/Kmol
  • Volume (V) =?

<h3>How to determine the volume </h3>

The volume of the gas can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

Divide both sides by P

V = nRT / P

V = (0.102 × 0.0821 × 305) / 0.95

V = 2.69 L

Thus, the volume of the gas is 2.69 L

Learn more about ideal gas equation:

brainly.com/question/4147359

#SPJ1

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Given the following balanced equation determine the amount of MgCl2 that can be produced from 65.0 grams of Mg. Mg + HCl --&gt;
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Answer:

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mass 65.0 mass 257.26

RFM 24 RFM 95

moles 2.708 moles 2.708

Explanation:

mass of MgCl = 257.26 grams

4 0
3 years ago
The molarity of a solution prepared by dissolving 4.11 g of NaI in enough water to prepare 312 mL of solution is
Dimas [21]

Answer:

The correct answer is 8.79 × 10⁻² M.

Explanation:

Based on the given information, the mass of NaI given is 4.11 grams. The molecular mass of NaI is 149.89 gram per mole. The moles of NaI can be determined by using the formula,

No. of moles of NaI = Weight of NaI/ Molecular mass

= 4.11 / 149.89

= 0.027420

The vol. of the solution given is 312 ml or 0.312 L

The molarity can be determined by using the formula,

Molarity = No. of moles/ Volume of the solution in L

= 0.027420/0.312

= 0.0879 M or 8.79 × 10⁻² M

6 0
2 years ago
WILL GIVE BRAINLIEST
Sav [38]

Answer:

the answer is A

Explanation:

5 0
3 years ago
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Answer:

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4 0
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What is the value of the specific heat capacity of liquid water in j/mol·°c?
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<span>he specific heat capacity of liquid water is 4.186 J/gm K.</span>
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