Question

What volume is occupied by 0.102 molmol of helium gas at a pressure of 0.95 atmatm and a temperature of 305 kk ?

Answer 1

The volume occupied by 0.102 mole of the helium gas is 2.69 L

Data obtained from the question

The following data were obtained from the question:

• Number of mole (n) = 0.102 moles
• Pressure (P) = 0.95 atm
• Temperature (T) = 305 K
• Gas constant (R) = 0.0821 atm.L/Kmol
• Volume (V) =?

How to determine the volume

The volume of the gas can be obtained by using the ideal gas equation as illustrated below:

PV = nRT

Divide both sides by P

V = nRT / P

V = (0.102 × 0.0821 × 305) / 0.95

V = 2.69 L

Thus, the volume of the gas is 2.69 L

Learn more about ideal gas equation:

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