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Zolol [24]
2 years ago
8

A sample of argon has a volume of 5.5 L and the pressure is 0.42 atm. If the final temperature is 30.° C, the final volume is 5.

7 L, and the final pressure is 0.8 atm, what was the initial temperature of the argon?
Chemistry
1 answer:
quester [9]2 years ago
6 0

Answer:

T=15.19°C

Explanation:

Given V1=5.5L P1=0.42atm T1=x

V2=5.7L P2=0.8atm T2=30°C

Assuming ideal gas By the law of gas

PV=nRT

Here n and R are constant throughout the process which means

\frac{PV}{T}=constant

\frac{P1V1}{T1}=\frac{P2V2}{T2}

\frac{5.5*0.42}{x}=\frac{5.7*0.8}{30}

on solving we get x=15.19°C

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Given that a chlorine-oxygen bond has an enthalpy of 243 kJ/mol , an oxygen-oxygen bond has an enthalpy of 498 kJ/mol , and the
Alecsey [184]

Explanation:

The chemical equation is as follows.

      \frac{1}{2}Cl_{2}(g) + \frac{1}{2}O_{2}(g) \rightarrow ClO(g)

And, the given enthalpy is as follows.

    \frac{1}{2}Cl_{2}(g) + O_{2}(g) \rightarrow ClO_{2}(g);  \Delta H = 102.5 kJ

    Cl-Cl = 243 kJ/mol,      O=O = 498 kJ/mol

Since, the bond enthalpy of Cl-Cl is not given so at first, we will calculate the value of Cl-Cl as follows.

   \Delta H = \sum \text{bond broken in reactants} - \sum \text{bond broken in products}

    102.5 = [(\frac{1}{2})x + 498] - [(2)(243)]

    102.5 = (\frac{1}{2})x + 498 - 486

     102.5 - 12 = \frac{x}{2}

           x = 181 kJ

Now, total bond enthalpy of per mole of ClO is calculated as follows.

       \Delta H = \sum E(\text{bond broken in reactants}) - \sum (\text{bond broken in products})

              x = [(\frac{1}{2})181 + (\frac{1}{2})498] - 243

                 = 339.5 - 243

                 = 96.5 kJ

Thus, we can conclude that the value for the enthalpy of formation per mole of ClO(g) is 96.5 kJ.

8 0
3 years ago
Which chemical is produced in the highest volume in both the united states and the world?
Komok [63]
<span>Sulfuric acid has the highest production levels of any chemical in both the US and the world. The US alone creates 37 million tons a year. It has many uses, but one of the largest is as fertilizer.</span>
8 0
2 years ago
Calculate the number of moles in a 14.5 gram sample of C4H10.
cricket20 [7]
Moles= mass divided by molar mass
Molar mass= 12.01(4) + 1.01(10)
                 = 58.14g/mol

Moles=14.5g / 58.14g/mol
         =0.249

Therefore there are approx 0.249 moles in a 14.5g sample of C4H10
6 0
2 years ago
State the Constituents of the following alloys:magnalium and bronze​
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Magnalium: Magnesium and Aluminum

Bronze: Copper, Tin, Arsenic, Phosphorus, Aluminum, Manganese and Silicon (whichever you learned in class from those)
8 0
2 years ago
Which of the following rules should you follow to balance chemical equations?
Firdavs [7]

Answer:

c. add coefficients as needed

Explanation:

A chemical equation is defined as the equation that shows changes in a chemical reaction. A chemical equation consist of reactant and product, reactant is at left side of the arrow and product is at right side of the arrow.

Reactant => Product

While balancing a chemical equation, the basic rule is to balance the coefficient as required. Coefficient represents the number of molecules and is used at front of a chemical symbol. Change in coefficient helps balance the number of atoms or molecules of the substances on both the sides of the arrow.

Subscripts are never allowed to change because it can change the chemical involved in the reaction.

Hence, the correct answer is "c. add coefficients as needed".

3 0
2 years ago
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