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Zolol [24]
3 years ago
8

A sample of argon has a volume of 5.5 L and the pressure is 0.42 atm. If the final temperature is 30.° C, the final volume is 5.

7 L, and the final pressure is 0.8 atm, what was the initial temperature of the argon?
Chemistry
1 answer:
quester [9]3 years ago
6 0

Answer:

T=15.19°C

Explanation:

Given V1=5.5L P1=0.42atm T1=x

V2=5.7L P2=0.8atm T2=30°C

Assuming ideal gas By the law of gas

PV=nRT

Here n and R are constant throughout the process which means

\frac{PV}{T}=constant

\frac{P1V1}{T1}=\frac{P2V2}{T2}

\frac{5.5*0.42}{x}=\frac{5.7*0.8}{30}

on solving we get x=15.19°C

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Compound X has a molar mass of 316.25 g*mol^-1 and the following composition:
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element:              phosphorus                       sulfur

co9mposition:      39.185%                            60.82%

divide with

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V₂ = 0.0613 L

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3 years ago
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