Equation: M1V1 = M2V2
Where M = concentration & V = volume
Step 1: Write down what is given and what you are trying to find
Given: M1 = 6.00M, V1 = 2.49mL, and V2 = 50.0mL
Find: M2
Step 2: Plug in the values into the equation
M1V1 = M2V2
(6.00M)(2.49mL) = (M2)(50.0mL)
Step 3: Isolate the variable (Divide both sides by 50.0mL so M2 is by itself)
(6.00M)(2.49mL) / (50.0mL) = M2
Answer: M2 = 0.30M
*Don't forget sig figs & units!
Answer:
9.18g
Explanation:
Step 1: Write the reduction half-reaction
Au³⁺(aq) + 3 e⁻ ⇒ Au(s)
Step 2: Calculate the mass of gold is produced when 15.0A of current are passed through a gold solution for 15.0min
We will use the following relationships:
- 1 mole of electrons has a charge of 96486 C (Faraday's constant).
- 1 mole of Au is produced when 3 moles of electrons circulate.
- The molar mass of Au is 196.97 g/mol.
The mass of gold produced is:

Answer:
<h3>it is hydrogen gas </h3>
3. the chemical equation is :
MgSO4 ( s ) + H2SO4 (aq)-->
MgSO4 (aq) + CO2 (g) + H2O (I)
THE IONISING OF H2SO4 IN SOLUTION IS CONPLEX
4. MAGNESIUM REACTION WITH DILUTE SULPHURIC ACID TO FORM
MAGNESIUM SULPHATE AND HYDROGEN GAS
Explanation:
hope it helps u
<span>Atomic radius generally increases as we move
</span><span>down a group and from right to left across a period.</span>