Answer:
A. The balanced equation is given below:
5C + 2SO2 —> CS2 + 4CO
B. 229.5 moles of carbon.
Explanation:
A. Step 1:
The equation for the reaction is given below:
C + SO2 —> CS2 + CO
A. Step 2:
Balancing the equation.
The above equation can be balanced as follow:
There are 2 atoms of S on the right side and 1 atom on the left side. It can be balance by putting 2 in front of SO2 as shown below:
C + 2SO2 —> CS2 + CO
There are 4 atoms of O on the left side and 1 on the right. It can be balance by putting 4 in front of CO as shown below:
C + 2SO2 —> CS2 + 4CO
There are a total of 5 atoms of C on the right side and 1 atom on the left. It can be balance by putting 5 in front of C as shown below:
5C + 2SO2 —> CS2 + 4CO
Now the equation is balanced
B. Determination of the number of moles of carbon needed to produce 45.90 moles of carbon disulfide.
This is illustrated below:
5C + 2SO2 —> CS2 + 4CO
From the balanced equation above,
5 moles of C produced 1 mole of CS2.
Therefore, Xmol of C will produce 45.90 moles of CS2 i.e
Xmol of C = 5 x 45.90
Xmol of C = 229.5 moles
229.5 moles of carbon is needed to produce 45.90 moles of carbon disulfide.
the balanced equation for the acid base reaction is as follows
NaOH + HCl ---> NaCl + H₂O
stoichiometry of NaOH to HCl is 1:1
the number of NaOH moles is - 0.139 mol/L x 0.0154 L = 0.00214 mol
the number of NaOH moles reacted = number of HCl moles reacted
therefore number of HCl moles reacted = 0.00214 mol
volume of HCl containing 0.00214 mol - 25.0 mL
number of HCl moles in 25.0 mL - 0.00214 mol
therefore number of HCl moles in 1000 mL - 0.00214 mol / 25.0 mL x 1000 mL/L
molarity of HCl is 0.0856 mol/L
concentration of HCl is 0.0856 M
Answer:
The correct answer would be A.
A mixture of sand and table salt can be separated by filtration because the substances in the mixture differ in solubility. Because sand and table salt have a different ability to dissolve they can easily be separated. What can be done to separate this mixture is to add water to it and stir it thoroughly. The salt will easily dissolve in water while the sand will stay insoluble. The filtration of this mixture will result in salt being drained off with water while only the sand will remain.
