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antoniya [11.8K]
4 years ago
8

A ______________________ is a simple machine that consists of an inclined plane wrapped around a central cylinder.

Physics
2 answers:
Svetach [21]4 years ago
7 0

the answer is B.screw

prohojiy [21]4 years ago
3 0

Answer:

The answer is B. Screw

Explanation:

A screw is a device that is used to hold an object. It has an elongated and screwed body that is inserted into the surface and with a head that has grooves so that a tool can be used and thus perform the corresponding force for fixing. The screw is an operator that derives directly from the inclined plane and always works associated with a threaded hole, that is, it is an inclined plane wound on a cylinder.

You might be interested in
How are liquids like gasses
Marta_Voda [28]

Answer: A liquid is made up of tiny vibrating particles of matter, such as atoms, held together by intermolecular bonds. Like a gas, a liquid is able to flow and take the shape of a container. Most liquids resist compression, although others can be compressed.

Explanation:

5 0
4 years ago
What happens when a particle of matter meets its corresponding antiparticle of antimatter?
shutvik [7]

Answer:

The combined mass of the two particles is completely transformed into energy (photons). This process is called matter-antimatter annihilation.

Explanation:

6 0
3 years ago
Suppose that the strings on a violin are stretched with the same tension and each has the same length between its two fixed ends
lesya692 [45]

Answer:

0.00384 kg/m

Explanation:

The fundamental frequency of string waves is given by

f=\frac{1}{2L}\sqrt{\frac{F}{\mu}}

For some tension (F) and length (L)

f\propto\frac{1}{\mu}

Fundamental frequency of G string

f_G=196\ Hz

Fundamental frequency of E string

f_E=659.3\ Hz

Linear mass density of E string is

\mu_E=3.4\times 10^{-4}\ kg/m

So,

\frac{F_G}{F_E}=\sqrt{\frac{\mu_E}{\mu_G}}\\\Rightarrow \frac{F_G^2}{F_E^2}=\frac{\mu_E}{\mu_G}\\\Rightarrow \mu_G=3.4\times 10^{-4}\times \frac{659.3^2}{196^2}\\\Rightarrow \mu_G=0.00384\ kg/m

The linear density of the G string is 0.00384 kg/m

4 0
3 years ago
Freight trains can produce only relatively small accelerations and decelerations. What is the final velocity, in meters per seco
Crank

Answer:

Explanation:

Initial velocity of train u = 3.4 m⁻¹ , Acceleration a = .065 ms⁻² ,

time t = 9.75 x 60 = 585 s.

v = u + at

= 3.4 + .065 x 585

= 41.425 m / s

distance travelled during the acceleration ( s )

s = ut + 1/2 at²

= 3.4 x 585 + .5 x .065 x 585²

= 1989 + 11122.31

= 13111.31 m .

again for slowing process

u = 41.425 m / s

v = u -at

0 = 41.425 - 0.625 t

t = 66.28 s

v² = u² - 2as

0 = 41.425² - 2 x .625 s

s = 1372.82 m

7 0
3 years ago
A heavier mass m1 and a lighter mass m2 are 17.0 cm apart and experience a gravitational force of attraction that is 9.70 10-9 N
puteri [66]

Answer:

The value of m1 is 4.2 kg and value of m2 is 1 kg.

Explanation:

Note:- The value of force is assumed to be 9.70*10^-9 N.

The gravitational force F is given by the formula,

F=Gm1m2 / r^2

where F is the force, G is the universal gravitational constant, m1 and m2 are masses and r is the distance between the masses.

Then the product of the masses is,

m1m2= Fr^2/G

Given F=9.70*10^-9 N, r is 17.0 cm which is equal to 0.17 m.

Therefore product m1m2= 9.70*10^-9 N *(0.17 m)^2 / 6.67*10^(-11) N m^2 kg^-2

m1m2= 4.20 kg^2

m1=4.20 kg^2/m2

The sum of masses is m1+m2=5.20 kg

 4.20/m2+m2=5.20

(m2)^2-5.20m2-4.20=0

After solving the above quadratic equation, mass m2 has values 4.2 kg and 1 kg.

By using m2=1 kg, m1 has greater mass 4.2 kg.

Check out similar question.

brainly.com/question/13014873

#SPJ10

4 0
2 years ago
Read 2 more answers
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