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3 years ago

A ______________________ is a simple machine that consists of an inclined plane wrapped around a central cylinder.

Physics

2 answers:

Svetach [21]3 years ago

7 0

the answer is B.screw

prohojiy [21]3 years ago

3 0

Answer:

The answer is B. Screw

Explanation:

A screw is a device that is used to hold an object. It has an elongated and screwed body that is inserted into the surface and with a head that has grooves so that a tool can be used and thus perform the corresponding force for fixing. The screw is an operator that derives directly from the inclined plane and always works associated with a threaded hole, that is, it is an inclined plane wound on a cylinder.

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This chemical equation represents a ______________ reaction.

Ede4ka [16]

Answer:

you didnt put anything

Explanation:

7 0

3 years ago

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A pilot heads his jet due east. The jet has a speed of 475 mi/h relative to the air. The wind is blowing due north with a speed

oksian1 [2.3K]

Explanation:

a. The velocity of the wind as a vector in component form will be represented as v vector:

$v=30j$

b.The velocity of the jet relative to the air as a vector in component form will be represented as u vector

$u=475i$

c. The true velocity of the jet as a vector will be represented as w:

$w=u+v$

$w=475i+30j$

d. The true speed of the jet will be calculated as:

$IwI=\sqrt{(475)^2+(30)^2}$

$IwI=\sqrt{225625+900}$

$IwI=\sqrt{226525}$

$IwI=476 mi/h$

e. The direction of the jet will be:

$tita=tan^{-1}\frac{30}{475}$

$tita=tan^{-1}(0.0632)$

$tita=3.62degrees,or,N86.38degreesS$

7 0

3 years ago

1. A large ball was let go on a hill and started rolling down with a constant acceleration of 4.2 m/s². What was the velocity of

pochemuha

Answer:

The velocity after 12s is 50.4m/s.

Explanation:

In acceleration formula make velocity the subject.

acceleration(a) = velocity(v)÷time(t)

<h3> velocity (v) = acceleration(a)×time(t)</h3>

V = 4.2m/s²×12s

V = 50.4m/s

Therefore the velocity after 12s is 50.4m/s.

8 0

2 years ago

A particle has a charge of -4.25 nC.

SpyIntel [72]

Answer:

-611.32 N/C

0.43723 m

Explanation:

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

q = Charge = -4.25 nC

r = Distance from particle = 0.25 m

Electric field is given by

$E=\dfrac{kq}{r^2}\\\Rightarrow E=\dfrac{8.99\times 10^9\times -4.25\times 10^{-9}}{0.25^2}\\\Rightarrow E=-611.32\ N/C$

The magnitude is 611.32 N/C

The electric field will point straight down as the sign is negative towards the particle.

$E=\dfrac{kq}{r^2}\\\Rightarrow r=\sqrt{\dfrac{kq}{E}}\\\Rightarrow r=\sqrt{\dfrac{8.99\times 10^9\times 4.25\times 10^{-9}}{13}}\\\Rightarrow r=1.71436\ m$

The distance from the electric field is 1.71436 m

4 0

3 years ago

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What kind of friction occurs as a fish swims through water?

Paul [167]

It must be sliding friction, because the fish is already in motion.

7 0

3 years ago