1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
tamaranim1 [39]
2 years ago
8

Write down Newton's second law in terms of momentum and acceleration. Write down this law in the form of differential equation (

DE).
Physics
1 answer:
svetoff [14.1K]2 years ago
3 0

Explanation:

According to Newton's second law of motion, the rate of change of momentum is directly proportional to the applied unbalanced force. The mathematical expression is given by:

F=\dfrac{d(mv)}{dt}

Where

F is the applied force

m is the mass of the object

v is the velocity with which it is moving

F=m\dfrac{dv}{dt}

Momentum of a particle is given by the product of mass and velocity as :

p=mv

Hence, this is the required solution.

You might be interested in
A rocket is moving at 1/4 the speed of light relative to Earth. At the center of this rocket a light suddenly flashes. To an obs
Sedaia [141]

Answer:

B. the light will reach the front of the rocket at the same instant that it reaches the back of the rocket.

Explanation:

To an observer at rest in the rocket who can't see either sides of the rocket, the speed of the light is constant which means the distance to the front or the back is same and would appear to reach the rocket at the same time.

Although from the point of view of the person on the earth, the front of the rocket is travelling in opposite direction of the light while the back of the rocket is moving closer to the light. This means that the distance travelled by the light going forward will be longer going backwards. And since the speed of light is constant in both directions, the light will reach the back of the rocket before it reaches the front  for the observer on the earth.

5 0
3 years ago
Read 2 more answers
Hari planted to go abroad. change into negative​
marishachu [46]

Answer:

Hari didn't plan to go abroad

Explanation:

Abroad planned to go to hari.

7 0
3 years ago
Compare and contrast the energy transfer of a roller coaster to that of a pendulum
Softa [21]

When the pendulum and roller coaster move to the top, its has more potential energy whereas when comes to the bottom has more kinetic energy.

<h3>Compare and contrast the energy transfer of a roller coaster to that of a pendulum:</h3><h3>What is the transfer of energy in a roller coaster?</h3>

The transfer of potential energy to kinetic energy occur when the roller coaster move along the track. As the motor pulls the cars to the top, the body has more potential energy whereas when the body comes to the bottom , it has kinetic energy in the object.

<h3>What is the energy transfer in a pendulum?</h3>

As a pendulum swings, its potential energy changes to kinetic energy and kinetic energy changes into potential energy. At the top more potential energy is present.

So we can conclude that When the pendulum and roller coaster move to the top, its has more potential energy whereas when comes to the bottom has more kinetic energy.

Learn more about energy here: brainly.com/question/13881533

#SPJ1

8 0
1 year ago
Help please I have to turn this in tonight!!
inna [77]

Answer:

True

Explanation:

i searched it up and well this thing is making me do it up till 20 characters long so yea

3 0
2 years ago
Read 2 more answers
A magnetic field is uniform over a flat, horizontal circular region with a radius of 1.50 mm, and the field varies with time. In
atroni [7]

Answer:

The average induced emf around the border of the circular region is 8.48\times 10^{-5}\ V.

Explanation:

Given that,

Radius of circular region, r = 1.5 mm

Initial magnetic field, B = 0

Final magnetic field, B' = 1.5 T

The magnetic field is pointing upward when viewed from above, perpendicular to the circular plane in a time of 125 ms. We need to find the average induced emf around the border of the circular region. It is given by the rate of change of magnetic flux as :

\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=A\dfrac{-d(B'-B)}{dt}\\\\\epsilon=\pi (1.5\times 10^{-3})^2\times \dfrac{1.5}{0.125}\\\\\epsilon=8.48\times 10^{-5}\ V

So, the average induced emf around the border of the circular region is 8.48\times 10^{-5}\ V.

6 0
3 years ago
Read 2 more answers
Other questions:
  • What is the energy of a photon of light with a wavelength of 3.10 × 10−7 m?
    5·1 answer
  • Two kittens are sleeping in a sunny spot. they are relying mainly on what kind of heat transfer?
    5·2 answers
  • Heating causes an object to dxpena
    8·1 answer
  • 2. Derive an expression for the final velocity of an object dropped from some height (h)
    11·1 answer
  • What is robot??????????
    13·1 answer
  • A boy having 0.2kg toy tied with a sting, having force 2N, angle 60º displaces it 5 m. What is the work done?
    10·1 answer
  • Dentify the following terms associated with the water cycle.
    13·1 answer
  • What type of objects exert gravitational pull? (5 points) Only living objects Only space objects All objects having mass All sub
    7·1 answer
  • Construct c = a + b by drawing and calculating the direction and magnitude of c. The direction should be
    10·1 answer
  • A machine which has an energy loss of 10% will have efficiency of​
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!