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stepan [7]
3 years ago
15

A cannonball is fired horizontally from the top of a cliff. the cannon is at height h = 80.0 m above ground level, and the ball

is fired with initial horizontal speed v0. assume acceleration due to gravity to be g = 9.80 m/s2 .assume that the cannon is fired at time t=0 and that the cannonball hits the ground at time tg. what is the y position of the cannonball at the time tg/2?
Physics
1 answer:
SOVA2 [1]3 years ago
6 0

Answer;

= 60 m

Explanation;

s = 80 m

= ½at² = ½ * 9.8m/s² * t² → t = 4.04 s  

At any time 0 ≤ t ≤ 4.04 s, height is  

y = Yo + ½at² = 80 m - 4.9m/s² * t²  

so at t = 4.04s/2 = 2.02 s,  

y = 80 m - 4.9m/s² * (2.02s)² = 60 m  

(so it drops 15 m during the first 2.02 s and 60 m during the second 2.02 s)

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when a electric current is passed through an insulated wire that is coiled around an iron core like a nail what is created?
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electromagnet

When a electric current is passed through an insulated wire that is coiled around an iron core, like a nail, an electromagnet is created.

8 0
3 years ago
Why is the sky blue?
Levart [38]

Answer:

Gases and particles in Earth's atmosphere scatter sunlight in all directions. Blue light is scattered more than other colors because it travels as shorter, smaller waves. This is why we see a blue sky most of the time.

7 0
3 years ago
A balloon filled with helium gas at 20°C occupies 4.91 L at 1.00 atm. The balloon is immersed in liquid nitrogen at -196°C, whil
mrs_skeptik [129]

Answer:

0.25 L

Explanation:

P_1 = Initial pressure = 1 atm

T_1 = Initial Temperature = 20 °C

V_1 = Initial volume = 4.91 L

P_2 = Final pressure = 5.2 atm

T_2 = Final Temperature = -196 °C

V_2= Final volume

From ideal gas law we have

\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}\\\Rightarrow V_2=\dfrac{P_1V_1T_2}{T_1P_2}\\\Rightarrow P_2=\dfrac{1\times 4.91(273.15-196)}{(20+273.15)\times 5.2}\\\Rightarrow V_2=0.24849\ L\approx 0.25\ L

The pressure experienced by the balloon is 0.25 L

7 0
3 years ago
Calculate the fraction of methyl isonitrile molecules that have an energy of 160.0 kJ or greater at 510 K .
soldi70 [24.7K]

Answer:

4.0932672025\times 10^{-17}

Explanation:

E_a = Activation energy = 160 kJ

T = Temperature = 510 K

R = Universal gas constant = 8.314 J/mol K

The fraction of energy is given by

f=e^{-\dfrac{E_a}{RT}}\\\Rightarrow f=e^{-\dfrac{160000}{8.314\times 510}}\\\Rightarrow f=4.0932672025\times 10^{-17}

The fraction of energy is 4.0932672025\times 10^{-17}

3 0
3 years ago
Assume a small 11 kg crate is attached to a parachute. The chute pulls up on the crate with 150 N.
MaRussiya [10]

Explanation:

a. The net force is the upward force of the chute minus the weight of the crate.

∑F = F − mg

∑F = 150 N − (11 kg) (9.8 m/s²)

∑F = 42.2 N

b. From Newton's second law, the net force equals the mass times acceleration:

∑F = ma

42.2 N = (11 kg) a

a = 3.84 m/s²

c. Acceleration is the change in velocity over change in time.  Assuming the crate is released from rest:

v = at + v₀

v = (3.84 m/s²) (5 s) + (0 m/s)

v = 19.2 m/s

3 0
3 years ago
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