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3 years ago

Describe the role of minerals in the formation of rocks

1 answer:

3 0

<span>Minerals make up rocks. The role of minerals in rock formation is largely dependent on how the rock is formed.</span>

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3. Force = _____ x _____?

harkovskaia [24]

Answer:

Explanation:

Force = mass * acceleration.

8 0

3 years ago

The moment of inertia of a uniform-density disk rotating about an axle through its center can be shown to be . This result is ob

Naddik [55]

(a) $0.2888 kg m^2$

The moment of inertia of a uniform-density disk is given by

$I=\frac{1}{2}MR^2$

where

M is the mass of the disk

R is its radius

In this problem,

M = 16 kg is the mass of the disk

R = 0.19 m is the radius

Substituting into the equation, we find

$I=\frac{1}{2}(16 kg)(0.19 m)^2=0.2888 kg m^2$

(b) 142.5 J

The rotational kinetic energy of the disk is given by

$K=\frac{1}{2}I\omega^2$

where

I is the moment of inertia

$\omega$ is the angular velocity

We know that the disk makes one complete rotation in T=0.2 s (so, this is the period). Therefore, its angular velocity is

$\omega=\frac{2\pi}{T}=\frac{2\pi}{0.2 s}=31.4 rad/s$

And so, the rotational kinetic energy is

$K=\frac{1}{2}(0.2888 kg m^2)(31.4 rad/s)^2=142.5 J$

(c) $9.07 kg m^2 /s$

The rotational angular momentum of the disk is given by

$L=I\omega$

where

I is the moment of inertia

$\omega$ is the angular velocity

Substituting the values found in the previous parts of the problem, we find

$L=(0.2888 kg m^2)(31.4 rad/s)=9.07 kg m^2 /s$

8 0

3 years ago

What equation represents the law of conservation of energy in closed system

svetoff [14.1K]

The first option.

The total mechanical energy before an action (which makes up PE and KE) equals the total mechanical energy after an action.

KEi + PEi = KEf + PEf

8 0

3 years ago

an eskimo pushes a loaded sled with a mass of 300kg over the frictionless surface of hard-packed snow.he exerts a constant 170n

Shalnov [3]

Answer:

0.567 m/s²

Explanation:

Newton's second law:

∑F = ma

170 N = (300 kg) a

a = 0.567 m/s²

Round as needed.

3 0

3 years ago

Read 2 more answers

Find an expression for the electric field E⃗ at the center of the semicircle. Hint: A small piece of arc length Δs spans a small

Hatshy [7]

Answer:

Electric Field a the centre $E=\dfrac{Q}{2\pi^2\epsilon_0 R^2}(-\vec j)$

Explanation:

<u>Given:</u>

Total charge on the semicircle =Q

Radius of the semicircle=R

Let consider a elemental charge on the semicircle at an angle $\theta\\$ with the horizontal. Since the The charge distribution is symmetrical about y axis so the there will symmetrical charge on other side. The horizontal component will cancel out each other and vertical component will get added so let dE be the electric Field due to elemental charge