If the 3 ohm resistor is in parallel to the 12 ohm (I can't see it in the image) then the current through it is 12V/3ohm = 4A Amps are Coulombs/s The charge on the electron is 1.6e-19C So 4 amps means 4/1.6e-19 = 2.5e19 electrons/s.
The reciprocal of this gives the number of electrons per second:
1/2.5e19 = 4e-20 s/(elect. charge)
The power in the 3 ohm resistor is 12*4=48W. This is Joules/sec. We know it takes on average 4e-20 s to get one electron charge through the resistor so we multiply: 48W * 4e-20s = 1.9e-18J
Note: In reality there are many electrons moving through the resistor together, and a single electron does not move this fast, but the total energy to do it would be equivalent to this.
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Below is the solution:
Output work = 108 J.
<span>Input work = 120 J </span>
<span>Efficiency = 108/120 = 9/10 = 90% </span>
<span>(Energy can be converted to heat in friction at the fulcrum, or useless potential energy distorting the crowbar)</span>
Answer:
Yes, it could discern all of them.
Explanation:
A compound bright field microscope can be used to illuminate samples in light microscopes. It has a very high resolution and it could detect samples as small as 200 to 300 nanometers. So, yes it could discern two objects separated by 3μm, 0.3μm, 300nm,3000Å.
<span>............D. Elliptical</span>
Answer: 24.97 kg
Explanation:
The gravitational force between two objects of masses M1, and M2 respectively, and separated by a distance R, is:
F = G*(M1*M2)/R^2
Where G is the gravitational constant:
G = 6.67*10^-11 m^3/(kg*s^2)
In this case, we know that
R = 0.002m
F = 0.0104 N
and that M1 = M2 = M
And we want to find the value of M, then we can replace those values in the equation to get
0.0104 N = (6.67*10^-11 m^3/(kg*s^2))*(M*M)/(0.002m)^2
(0.0104 N)*(0.002m)^2/(6.67*10^-11 m^3/(kg*s^2)) = M^2
623.69 kg^2 = M^2
√(623.69 kg^2) = M = 24.97 kg
This means that the mass of each object is 24.97 kg
