The rate of energy absorption from the outdoor air is 4400 KJ/h
<u>Explanation:</u>
Coefficient of performance (COP), is an expression of the efficiency of a heat pump. When calculating the COP for a heat pump, the heat output from the condenser (Q) is compared to the power supplied to the compressor (W).
The coefficient of performance,
We replace the value in the equation with given data,
By making a conversion, we get
The energy balance,
Now, replace the values in the equation, we get
Answer:
A) 8.03Hz
Explanation:
f = V/λ
Where wavelength( λ )= 30m
Speed (V) =241m/S
f= 241/30=8.03Hz
Answer:
- the power to the air is 850 MW
- mass flow rate of the air is 84577.11 kg/s
Explanation:
Given the data in the question;
Net power generated; = 150 MW
Heat input; = 1000 MW
Power to air = ?
For closed cycles
Power to air Q₀ = Heat input; - Net power generated;
we substitute
Power to air Q₀ = 1000 - 150
Q₀ = 850 MW
Therefore, the power to the air is 850 MW
given that ΔT = 10 °C
mass flow rate of air required will be;
⇒ Q₀ / CpΔT
we know that specific heat of air at p=c ; Cp = 1.005 kJ/kg.K
we substitute
⇒ ( 850 × 10³ ) / [ 1.005 × 10 ]
⇒ ( 850 × 10³ ) / 10.05
⇒ 84577.11 kg/s
Therefore, mass flow rate of the air is 84577.11 kg/s
Answer:
Kinetic energy
Explanation:
Kinetic energy is the energy of motion, and the arrow is in motion.
Well, all the words are common, but I try to answer in my way. The way how light is used to study space is finding distance between the planets, which is called a light year. According to the <span>scientist's beliefs the space is but a vaccum and the only body that can travel through it is light, that's why light is very importand for discovering space.
</span>Hope you will find it helpful!