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GarryVolchara [31]
3 years ago
8

A student performing this experiment weights out 0.6680 grams of an antacid tablet. It is was determined that this tablet contai

ned 0.4210 grams of CaCO3. What is the percent CaCO3 of this tablet?
Chemistry
1 answer:
Rufina [12.5K]3 years ago
3 0

Answer:

63 wt%

Explanation:

0.4210/0.6680

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The relationship between moles and volume, when pressure and temperature of a gas are held constant, is: V/n =
Dvinal [7]

Answer:

If the moles of gas are tripled, the volume must also triple.

Explanation:

According to Avogadro law,

Equal volume of all the gases at same temperature and pressure have equal number of molecules.

The number of moles and volume are directly related to each other. By increasing the number of moles volume also goes to increase with same ratio.

When number of moles decreases the volume also goes to decrease at constant temperature and pressure.

Mathematical expression:

V ∝ n

V = Kn

V/n = k

When volume is changed from V₁ to V₂ by changing the number of moles from n₁ to n₂. Then expression will be,

V₁/n₁ = V₂/n₂

5 0
3 years ago
The main type of attractive forces between molecules of carbon tetrabromide (cbr4) are:_______
romanna [79]

Answer:

Vanderwaals forces

Explanation:

CBr4 is a nonpolar molecule, nonpolar molecules usually possess vanderwaals forces between their molecules as their main attractive force.

CBr4 is nonpolar because the tetrahedral arrangement of the C-Br bonds cancel out the individual dipole moments of each C-Br bond thereby making the compound nonpolar, hence the answer above.

8 0
3 years ago
The rate constant of a reaction is 4.7×10−3 s−1 at 25°C, and the activation energy is 33.6 kJ/mol. What is k at 75°C?
vodomira [7]

Answer:

k is 3,18*10⁻² s⁻¹ at 75°C

Explanation:

following Arrhenius equation:

k= k₀*e^(-Ea/RT)

where k= rate constant , k₀= frequency factor , Ea= activation energy , R= universal gas constant T=absolute temperature

then for T₁=25°C =298 K

k₁= k₀*e^(-Ea/RT₁)

and for T₁=75°C = 348 K

k₂= k₀*e^(-Ea/RT₂)

dividing both equations

k₂/k₁= e^(-Ea/RT₂+Ea/RT₁ )

k₂= k₁*e^[-Ea/R*(1/T₂-1/T₁ )]

replacing values

k₂= k₁*e^[-Ea/R*(1/T₂-1/T₁ )] = 4,7*10⁻³ s⁻¹ *e^[-33.6*1000 J/mol /8.314 J/molK*(1/ 348 K -1/298 K )] = 3,18*10⁻² s⁻¹

thus k is 3,18*10⁻² s⁻¹ at 75°C

6 0
4 years ago
A meteorologist wants to create a visual aid different gases in earths atmosphere which type of chart or graph would best convey
Karolina [17]

Answer:

A pie chart

Explanation:

A pie chart would be the ideal type of chart to create this visual aid. A pie chart is simpler visually and easily understood. It can show data as portions or percentages of a whole. Since what they want is to present the different gases found in Earth's atmosphere, they can show what percentage of the different gases make up the atmosphere.

It is simpler because the size of each portion or "slice" of the pie chart itself can reveal a lot about the data without even reading the numbers.

4 0
3 years ago
Read 2 more answers
The lines in an element's atomic spectrum result from
IRINA_888 [86]

Answer:

electron moving from a lower energy to a higher level of energy

7 0
3 years ago
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