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Arte-miy333 [17]
1 year ago
14

the titration of a polyprotic acid with sufficiently different pka 's displays two equivalence points. why?

Chemistry
1 answer:
morpeh [17]1 year ago
4 0

If Ka1 and Ka2 are sufficiently distinct and a polyprotic acid is titrated with a strong base, the pH curve will contain two equivalence points because the two acidic protons will be titrated sequentially.

<h3>What is titration?</h3>

Titration is a method of chemical analysis in which the amount of a sample's constituents is determined by adding a precise amount of a different substance—one that the desired constituent reacts with in a specific, known proportion—to the sample being tested.

The titrating reagent, or titrant, is gradually added to the process using a standard solution (i.e., a solution of known concentration), which is administered using a burette, which is essentially a long, graduated measurement tube with a stopcock and a delivery tube at its bottom end. The addition comes to an end at the comparable point.

To know more about titration, visit:

brainly.com/question/2728613
#SPJ4

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Look at picture please
Tom [10]

Answer:

Keep temperature constant and increase the pressure of the reaction. The rate of reaction increases.

Explanation:

First of all, the question is asking us to design an experiment to investigate the effect of pressure on the rate of reaction hence the pressure can not be held constant since it is the variable under investigation. This eliminates the first option.

Secondly, increasing the pressure of the reaction means that particles of the gas collide more frequently leading to a greater number of effective collisions and a consequent increase in the rate of reaction according to the collision theory.

Hence the answer above.

3 0
2 years ago
Calculate δ h for the reaction:no (g) + o2 (g) ↔ no2 (g). given: 2o3(g) ↔ 3o2(g) δh=-426 kj o2(g) ↔ 2o(g) δh=+ 490 kj no(g) + o3
maks197457 [2]
To calculate the <span>δ h, we must balance first the reaction: 

NO + 0.5O2 -----> NO2

Then we write all the reactions,

2O3 -----> 3O2    </span><span>δ h = -426 kj        eq. (1)

O2 -----> 2O    </span><span>δ h = 490 kj             eq. (2)

NO + O3 -----> NO2 + O2    </span><span>δ h = -200 kj          eq. (3)


We divide eq. (1) by 2, we get

</span>O3 -----> 1.5O2    δ h = -213  kj             eq. (4)

Then, we subtract eq. (3) by eq. (4) 

NO + O3 ----->  NO2 + O2   δ h = -200 kj
-       (O3 -----> 1.5 O2         δ h = -213  kj)
NO -----> NO2 - 0.5O2        δ h = 13  kj               eq. (5)


eq. (2) divided by -2. (Note: Dividing or multiplying by negative number reverses the reaction)

O -----> 0.5O2  <span>δ h = -245  kj         eq. (6)
</span>
Add eq. (6) to eq. (5), we get

NO -----> NO2 - 0.5O2        δ h = 13  kj 
+  O -----> 0.5O2                 δ h = -245  kj
NO + O ----> NO2               δ h = -232 kj

<em>ANSWER:</em> <em>NO + O ----> NO2               δ h = -232 kj</em>


4 0
3 years ago
Which Florida law requires owners and operators of motor vehicles to be financially responsible for damages and/or injuries they
s344n2d4d5 [400]

The answer in the given sentence above is the financial responsibility law as this law provides operators and owners to be held liable of the damages that they had provided or injuries that has proven to be their fault and they would likely provide financial support or payment to those affected.

3 0
3 years ago
Read 2 more answers
If a substance has a half life of 58 years and starts with 500 g radioactive, how much remains radioactive after 30 years?
Vilka [71]

Answer:

A = 349 g.

Explanation:

Hello there!

In this case, since the radioactive decay kinetic model is based on the first-order kinetics whose integrated rate law is:

A=Ao*exp(-kt)

We can firstly calculate the rate constant given the half-life as shown below:

k=\frac{ln(2)}{t_{1/2}} =\frac{ln(2)}{58year}=0.012year^{-1}

Therefore, we can next plug in the rate constant, elapsed time and initial mass of the radioactive to obtain:

A=500g*exp(-0.012year^{-1} *30year)\\\\A=349g

Regards!

5 0
3 years ago
5.25 ml of substance A has a mass of 3.9 g and 6.24 ml of substance B has a mass of 4.4 g. Which liquid is more dense?
Viktor [21]
Substance A because it weighs less
5 0
2 years ago
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