Horizontal speed = 24.0 m/s
height of the cliff = 51.0 m
For the initial vertical speed will are considering the vertical component. Therefore,
Since the student fires the canonical ball at the maximum height of 51 m, the initial vertical velocity will be zero. This means
let's find how long the ball remained in the air.
Finally, let's find the how far from the base of the building the ball landed(horizontal distance)
Answer:
V=?
S= 40m
t=5s
V=S/t
V=40/5
V=8m/s
3 meters
Explanation:
add up dum boi
The answer to this problem is M1v1-m2v2=(m1+m2)v