Ask question

Ask question

All categories

3 years ago

8

The purpose of _______'s ministry was to bring the nation in exile back to the God of their covenant

2 answers:

Anit [1.1K]3 years ago

6 0

The answer would be Jeremiah

ExtremeBDS [4]3 years ago

3 0

The correct answer would be Jeremiah

You might be interested in

A carmaker has designed a car that can reach a maximum acceleration of 12 meters per second the cars mass is 1515 assuming the s

Rudiy27

The answer is attached. Also, you should know that the unit for acceleration is m/s2 and for velocity it is m/s.

5 0

3 years ago

Read 2 more answers

Compare the results of applying the acceleration equation in the following 2 cases : (1) an object that goes from 0 to 10 m/s in

erastovalidia [21]

2oeuhehdhfhdhfhdjdjdndndjjfjdjfjgfjfjjrjrj

8 0

3 years ago

Please i really need help..

stiv31 [10]

C.) chemical to electrical to light

6 0

3 years ago

Read 2 more answers

What is an astronomer? Answer in the simpliest way please.

Sphinxa [80]

They would be an expert in astronomy
astronomy:the branch of science that deals with celestial objects

8 0

3 years ago

An AM radio station broadcasts isotropically (equally in all directions) with an average power of 3.40 kW. A receiving antenna 6

lara [203]

To solve the problem we will apply the concepts related to the Intensity as a function of the power and the area, as well as the electric field as a function of the current, the speed of light and the permeability in free space, as shown below.

The intensity of the wave at the receiver is

$I = \frac{P_{avg}}{A}$

$I = \frac{P_{avg}}{4\pi r^2}$

$I = \frac{3.4*10^3}{4\pi(4*1609.34)^2} \rightarrow 1mile = 1609.3m$

$I = 6.529*10^{-6}W/m^2$

The amplitude of electric field at the receiver is

$I = \frac{E_{max}^2}{2\mu_0 c}$

$E_{max}= \sqrt{2I\mu_0 c}$

The amplitude of induced emf by this signal between the ends of the receiving antenna is

$\epsilon_{max} = E_{max} d$

$\epsilon_{max} = \sqrt{2I \mu_0 cd}$

Here,

I = Current

$\mu_0$ = Permeability at free space

c = Light speed

d = Distance

Replacing,

$\epsilon_{max} = \sqrt{2(6.529*10^{-6})(4\pi*10^{-7})(3*10^{8})(60.0*10^{-2})}$

$\epsilon_{max} = 0.05434V$

Thus, the amplitude of induced emf by this signal between the ends of the receiving antenna is 0.0543V

6 0

3 years ago