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svetoff [14.1K]
1 year ago
9

identify the precipitate(s) of the reaction that occurs when a silver nitrate solution is mixed with a sodium chloride solution.

Chemistry
1 answer:
zlopas [31]1 year ago
6 0

The precipitate of reaction that occurs when silver nitrate solution is mixed with sodium chloride solution is of silver chloride (AgCI).

The chemical equation for this precipitation reaction is as following:

AgNO3(aq) + NaCl(aq) --> AgCl(s) [precipitate]+NaNO3(aq)

  • Silver Chloride is a chemical compound which is poorly soluble in water because the chemical bond between Ag+ and Cl is very strong as the two ions are nearly the same size and have similar electronic densities.
  • If the chemical bond is strong, it is difficult for water molecules to break this bond to surround the individual ions, thus solubility will decrease.

learn more about precipitate at

Brainly.com brainly.com/question/13877944

#SPJ4

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The empirical formula of a compound is CH. At 200 degree C, 0.145 g of this compound occupies 97.2 mL at a pressure of 0.74 atm.
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Answer:

The molecular formula = C_{6}H_{6}

Explanation:

Given that:

Mass of compound, m = 0.145 g

Temperature = 200 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

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Considering,  

n=\frac{m}{M}

Using ideal gas equation as:

PV=\frac{m}{M}RT

where,  

P is the pressure

V is the volume

m is the mass of the gas

M is the molar mass of the gas

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the values in the above equation as:-

0.74\times 0.0972=\frac{0.145}{M}\times 0.0821\times 473.15

M=78.31\ g/mol

The empirical formula is = CH

Molecular formulas is the actual number of atoms of each element in the compound while empirical formulas is the simplest or reduced ratio of the elements in the compound.

Thus,  

Molecular mass = n × Empirical mass

Where, n is any positive number from 1, 2, 3...

Mass from the Empirical formula = 12 + 1 = 13 g/mol

Molar mass = 78.31 g/mol

So,  

Molecular mass = n × Empirical mass

78.31 = n × 13

⇒ n ≅ 6

The molecular formula = C_{6}H_{6}

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