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vladimir2022 [97]
2 years ago
4

select the single best answer. assuming acid strength relates directly to the number of o atoms bonded to the central atom, sele

ct which of the following acids would have the greatest strength: hno3 (or hono2) h2n2o2 [or (hon)2] hno2 (or hono)
Chemistry
1 answer:
snow_tiger [21]2 years ago
5 0

The acid HONO2 has the highest acidic strength out of H2N2O2, HNO2

  • Acid is a substance that donates a proton.
  • The number of atoms attached to a molecule determines its acidic strength.
  • HNO3 has highest number of atom attached to the central atom.
  • So it has the highest acidic strength.
  • Acidic strength is decided on the basis of Ka value.
  • Acid strength is the tendency of an acid, symbolised by the chemical formula , to dissociate into a proton, , and an anion,
  • All others acids are less acidic than HONO2.
  • Acid strength is the measure of the ability of the acid to lose its H+ ion. Example of strong acids are hydrochloric acid, sulphuric acid.
  • The relative strength of an acid can be predicted based on its chemical structure. In general, an acid is stronger when the H–A bond is more polar.

To learn more about acidic strength visit:

brainly.com/question/3223615

#SPJ4

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Could somebody please give me an example of some physical properties for any substance?
KIM [24]

Answer:

A physical property is a characteristic of matter that is not associated with a change in its chemical composition. Familiar examples of physical properties include density, color, hardness, melting and boiling points, and electrical conductivity.

Explanation:

6 0
3 years ago
A chemical reaction involves reactant species A, B, and C. Leaving all other factors identical, doubling the concentration of sp
umka21 [38]

Answer:

Rate = k . [B]² . [C]

Explanation:

The dependence of the reaction rate on the concentration of the reactants is given by the reaction order of each one, as shown in the rate equation.

Rate=k.[A]^{x} .[B]^{y} .[C]^{z}

where,

k is the rate constant

x, y, z are the reaction orders.

  • <em>The rate of reaction is not affected by changing the concentration of species A.</em> This means that the reaction order for A is x = 0 since when its concentration changes, the rate stays the same.
  • <em>Leaving all other factors identical, doubling the concentration of species B increases the rate by a factor of 4.</em> This means that the reaction order for B is y = 2, so when the concentration is doubled, the new rate is 2² = 4 times the initial rate.
  • The rate of the reaction is linearly dependent on the concentration of C. This means that the reaction order for C is z = 1, that is, a linear dependence.

All in all, the rate equation is:

Rate = k . [B]² . [C]

3 0
3 years ago
The electrolysis of water forms H2 and O2.
Monica [59]

Answer:

67.5% ≅ 67.6%

Explanation:

Given data:

Mass of water = 17.0 g

Mass of oxygen produced  (actual yield)= 10.2 g

Percent yield of oxygen = ?

Solution:

Chemical equation:

2H₂O   →   2H₂ + O₂

Number of moles of water:

Number of moles = mass/ molar mass

Number of moles = 17.0 g/ 18.016 g/mol

Number of moles = 0.944 mol

Now we will compare the moles of oxygen with water to know the theoretical yield of oxygen.

                        H₂O       :        O₂

                          2          :         1

                        0.944      :      1/2×0.944 = 0.472 mol

Mass of oxygen:

Mass = number of moles× molar mass

Mass = 0.472 mol × 32 g/mol

Mass = 15.104 g

Percent yield:

Percent yield = [Actual yield / theoretical yield] × 100

Percent yield = [ 10.2 g/ 15.104 g] × 100

Percent yield = 0.675 × 100

Percent yield = 67.5%

5 0
3 years ago
Read 2 more answers
A 155.0 g piece of copper at 128 oC is dropped into 250.0 g of water at 17.9 oC. (The specific heat of copper is 0.385 J/goC.) C
Mamont248 [21]

Answer:

T_{eq}=23.85^oC

Explanation:

Hello,

In this case, as the copper's heat loss is gained by the water, the following energetic relationship is:

\Delta H_{Cu}=-\Delta H_{H_2O}

Therefore the equilibrium temperature shows up as:

m_{Cu}Cp_{Cu}(T_{Cu}-T{eq}) = m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})\\\\T_{eq}=\frac{m_{Cu}Cp_{Cu}T_{Cu}-m_{H_2O}Cp_{H_2O}T_{H_2O}}{m_{Cu}Cp_{Cu}-m_{H_2O}Cp_{H_2O}} \\

Thus, by knowing that water's heat capacity is 4.18J/g°C, one obtains:

T_{eq}=\frac{155.0g*0.385\frac{J}{g^oC}*128^oC+250.0g*4.18\frac{J}{g^oC}*17.9^oC}{155.0g*0.385\frac{J}{g^oC}+250.0g*4.18\frac{J}{g^oC}}=23.85^oC

Best regards.

6 0
3 years ago
Read 2 more answers
Please help. balance this equation
Nuetrik [128]

Answer:

k=2

ci=2

o=6

k=2

ci=2

o=6

Explanation:

4 0
3 years ago
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