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3 years ago

The electrolysis of water forms H2 and O2.

Chemistry

2 answers:

Monica [59]3 years ago

5 0

Answer:

67.5% ≅ 67.6%

Explanation:

Given data:

Mass of water = 17.0 g

Mass of oxygen produced (actual yield)= 10.2 g

Percent yield of oxygen = ?

Solution:

Chemical equation:

2H₂O → 2H₂ + O₂

Number of moles of water:

Number of moles = mass/ molar mass

Number of moles = 17.0 g/ 18.016 g/mol

Number of moles = 0.944 mol

Now we will compare the moles of oxygen with water to know the theoretical yield of oxygen.

H₂O : O₂

2 : 1

0.944 : 1/2×0.944 = 0.472 mol

Mass of oxygen:

Mass = number of moles× molar mass

Mass = 0.472 mol × 32 g/mol

Mass = 15.104 g

Percent yield:

Percent yield = [Actual yield / theoretical yield] × 100

Percent yield = [ 10.2 g/ 15.104 g] × 100

Percent yield = 0.675 × 100

Percent yield = 67.5%

LenaWriter [7]3 years ago

4 0

Answer:

67.6

Explanation:

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Romashka [77]

Since you have not included the chemical reaction I will explain you in detail.

1) To determine the limiting agent you need two things:

- the balanced chemical equation

- the amount of every reactant involved as per the chemical equation

2) The work is:

- state the mole ratios of all the reactants: these are the ratios of the coefficientes of the reactans in the balanced chemical equation.

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number of moles = (mass in grams) / (molar mass)

- set the proportion with the two ratios (theoretical moles and actual moles)

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3) Example: determine the limiting agent in this reaction if there are 100 grams of each reactant:

i) Chemical equation: H₂ + O₂ → H₂O

ii) Balanced chemical equation: 2H₂ + O₂ → 2H₂O

iii) Theoretical mole ration of the reactants: 2 moles H₂ : 1 mol O₂

iv) Covert 100 g of H₂ into number of moles

n = 100g / 2g/mol = 50 mol of H₂

v) Convert 100 g of O₂ to moles:

n = 100 g / 32 g/mol = 3.125 mol

vi) Actual ratio: 50 mol H₂ / 3.125 mol O₂

vii) Compare the two ratios:

2 mol H₂ / 1 mol O ₂ < 50 mol H₂ / 3.125 mol O₂

Conclusion: the actual ratio of H₂ to O₂ is greater than the theoretical ratio, meaning that the H₂ is in excess respect to the O₂. And that means that O₂ will be consumed completely while some H₂ will remain without react.

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Natasha_Volkova [10]

Answer:

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Explanation:

Hello!

In this case, since the formula for calculating the molarity is:

$M=n/V$

Whereas n stands for moles and V for the volume in liters; we can solve for n as shown below when we are given the volume and the molarity:

$n=V*M$

Thus, we plug in the given data to obtain:

$n=2.5L*1.75mol/L=4.4mol$

Best regards!

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Aliun [14]

Answer:

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