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3 years ago

The electrolysis of water forms H2 and O2.

Chemistry

2 answers:

Monica [59]3 years ago

5 0

Answer:

67.5% ≅ 67.6%

Explanation:

Given data:

Mass of water = 17.0 g

Mass of oxygen produced (actual yield)= 10.2 g

Percent yield of oxygen = ?

Solution:

Chemical equation:

2H₂O → 2H₂ + O₂

Number of moles of water:

Number of moles = mass/ molar mass

Number of moles = 17.0 g/ 18.016 g/mol

Number of moles = 0.944 mol

Now we will compare the moles of oxygen with water to know the theoretical yield of oxygen.

H₂O : O₂

2 : 1

0.944 : 1/2×0.944 = 0.472 mol

Mass of oxygen:

Mass = number of moles× molar mass

Mass = 0.472 mol × 32 g/mol

Mass = 15.104 g

Percent yield:

Percent yield = [Actual yield / theoretical yield] × 100

Percent yield = [ 10.2 g/ 15.104 g] × 100

Percent yield = 0.675 × 100

Percent yield = 67.5%

LenaWriter [7]3 years ago

4 0

Answer:

67.6

Explanation:

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P=atm

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$(V-nb)=\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}$

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