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Aliun [14]
3 years ago
5

As its speed increases, what happens to its energy of motion?

Physics
1 answer:
irina [24]3 years ago
5 0

Answer:

The energy of motion increases

Explanation:

The reason the energy of motion increases is because as the speed increases there is more motion and more energy

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Spheres are not perfect in space. But <> is in the cause of their shape. ​
MariettaO [177]

Answer:

\boxed {  \tt{gravitational \: pull(force)}}

8 0
3 years ago
Please answer i need help asap!!!
Alexus [3.1K]
The time to distance ratio is 2.1:1 , making the first time 5 seconds, the first distance 18.9 m, and the second time 15 seconds. I hope this helps!
5 0
3 years ago
3. A bottle of vitamin C contains 100 tablets and weighs 80 g. If the
Elan Coil [88]

Answer:

a

0.57g

b

20.52

c

28.5

Explanation:

a

The bottle weighs 80g with tablets

If the bottle alone weighs 23g, the tablets weigh 57g

100 tablets weigh 57g, 1 tablet weighs 0.57g

b

0.57g is one tablet, so to achieve 36 tablets we must multiply by 36

0.57 multiplied by 36 is 20.52

c

To find 50 tablets we can use the same method we used before or a slightly faster method

100 tablets is 57g, so all we have to do is halve to find 50

57 divided by 2 is 28.5

4 0
2 years ago
the momentum of a spring coil when the external compressing force is removed b the difference between the final momentum and the
Fed [463]

Answer:

the correct one is b

the difference between the final moment and the initial moment

Explanation:

The momentum is related to the moment

          I = ΔP

          ∫ F dt = p_f - p₀

where p_f and p₀ are the final and initial moments, respectively

When checking the different answers, the correct one is b

the difference between the final moment and the initial moment

7 0
3 years ago
1. What is the intensity of a sound when an observer is 10.0 m from the speaker
Nana76 [90]

Answer:

About 133 db.

Explanation:

Sound Intensity Level in db (SIL db) is equal to 10log (base 10) times the ratio of the sound intensity at 200 watts (I) relative to the sound intensity of  the reference sound intensity (I sub 0), which by default is equal to 10⁻¹² W/m² or 0 dB.

I = 200 w / 10 m^2 = 20 w per square meter  

I sub 0 = 10^-12 w per square meter

SIL = 10log ( I / I sub o) = 20 / 10^-12 = 10log ( 20^12) = 10 ( 13.3 ) = 133 db

Hope I typed this part correctly. Hard to get it in without being able to do exponents, etc. :D

8 0
3 years ago
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