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Nutka1998 [239]
3 years ago
8

What is the mass of an object that requires a force of 30 N to accelerate at a rate of 5 m/sec2 ?

Physics
1 answer:
Anastaziya [24]3 years ago
8 0
M=F/A
Which means 30 divided by 5 m/s is 6kg(mass)
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Answer:

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How does a plasma differ from a gas
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3 0
3 years ago
An AC generator has 80 rectangular loops on its armature. Each loop is 12 cm long and 8 cm wide. The armature rotates at 1200 rp
Sauron [17]

Answer: 28.96 V

Explanation:

Given

No of loops on the armature, N = 80

Length of the loop, l = 12 cm = 0.12 m

Width of the loop, b = 8 cm = 0.08 m

Speed of the armature, 1200 rpm

Magnetic field of the loop, B = 0.30 T

To solve this, we use the formula

V(max) = NBAω

Where,

A = area of loop

A = l*b = 0.12 * 0.08

A = 0.0096 m²

ω = 1200 rpm = 1200 * 2π/60 rad/s

ω = (1200 * 2 * 3.142) / 60

ω = 7540.8 / 60

ω = 125.68 rad/s

Substituting the values into the formula

V(max) = NBAω

V(max) = 80 * 0.30 * 0.0096 * 125.68

V(max) = 80 * 0.362

V(max) = 28.96 V

Therefore, the maximum output voltage of the generator would be 28.96 V

5 0
3 years ago
**URGENT** Roberto plans to use two transformers to reduce a voltage of 120 V to 4 V. He uses a transformer that has 300 coils i
skelet666 [1.2K]

As we know that in transformers we have

\frac{V_s}{V_p} = \frac{N_s}{N_p}

here we know that

V_s = 4 Volts

V_p = 120 Volts

N_s = 50 coils

N_p = 300 coils

now from above equation we will have

\frac{V}{120} = \frac{50}{300}

V = 20 Volts

now we have to reduce this voltage to final voltage of V = 4 V

so again we will have

\frac{V_s}{V_p} = \frac{N_s}{N_p}

\frac{4}{20} = \frac{N_s}{N_p}

\frac{N_s}{N_p} = \frac{1}{5}

so we need to take such a winding whose ratio is 1:5

So it is satisfied in X

N_p = 60

N_s = 12

so answer will be

<u>B)-   X</u>

3 0
3 years ago
Read 2 more answers
Name two objects that use electric motors and are commonly found in houses.
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<span>Refrigerator - Contains Induction motor in compressor.
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4 0
3 years ago
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