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a_sh-v [17]
2 years ago
15

Just asking how everyone is doing cause of the virus

Physics
2 answers:
kow [346]2 years ago
5 0

We out here living ig? I’m bored

Bess [88]2 years ago
3 0

Answer:

We are all fiine

Explanation:

How are you doing also

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The speed of a projectile when it reaches its maximum height is 0.58 times its speed when it is at half its maximum height. What
Ne4ueva [31]

Speed of the projectile at its maximum height is only along horizontal direction

so at highest point

v_1 = v_x

now when he is at half of the maximum height the speed will be in x and y direction both

v_2 = \sqrt{v_y^2 + v_x^2}

here it is given that

v_1 = 0.58 v_2

v_x = 0.58\sqrt{v_x^2 + v_y^2}

2.97 v_x^2 = v_x^2 + v_y^2

1.97 v_x^2 = v_y^2

also we know that

v_y^2 = v_{iy}^2 - 2 g \frac{H}{2}

here we know that maximum height is given as

H = \frac{v_{iy}^2}{2g}

v_y^2 = v_{iy}^2 - 2 g\frac{v_{iy}^2}{4g}

v_y^2 = \frac{v_{iy}^2}{2}

now from above

1.97 v_x^2 = \frac{v_{iy}^2}{2}

1.98 v_x = v_{iy}

also we know that angle of projection is

tan\theta = \frac{v_{iy}}{v_x}

tan\theta = \frac{1.98v_x}{v_x}

so angle is

\theta = tan^{-1} 1.98

\theta = 63.3 degree

6 0
3 years ago
HELP ASAP!! WILL MARK BRAINLIEST
Kitty [74]

Answer:

A

Explanation:

The magnet can always attract other things.

8 0
3 years ago
Read 2 more answers
In concave mirror, the size of image depends upon
irina1246 [14]

Answer:

The distance of the object placed on the principal axis from the concave mirror.

Explanation:

In a concave mirror, the nature of the image formed formed by the object placed in front of the mirror depends on the position of the object placed in from of the mirror. It all depends on the distance between the mirror and the object placed on the principal axis.

The closer the object is to the lens, the more larger or magnified the image formed will be. For example an object placed between the focal point and the pole of a concave produces a much larger image than an object placed beyond the centre of curvature of such mirror.

8 0
3 years ago
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A carmaker has designed a car that can reach a maximum acceleration of 12 meters/second2. The car’s mass is 1,515 kilograms. Ass
Vlada [557]
1) 15 / 12 = 1.25 ratio
2) to increase acceleration  1.25 times (with same F, or same engine) you have to lower mass 1.25 times
3) 1515/1.25 = 1212 kg

choose A

6 0
2 years ago
A car is moving in a straight line with the same speed of 100 m/s ,the acceleration in this
Amiraneli [1.4K]

Answer:

a = 0m/s²

Explanation:

Average acceleration = (change in velocity)/(time it takes). Since the car's change in velocity is zero, its acceleration is zero.

4 0
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