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a_sh-v [17]
3 years ago
15

Just asking how everyone is doing cause of the virus

Physics
2 answers:
kow [346]3 years ago
5 0

We out here living ig? I’m bored

Bess [88]3 years ago
3 0

Answer:

We are all fiine

Explanation:

How are you doing also

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A television has a mass of 19 kg. What is the weight of the television?
soldi70 [24.7K]
That depends on how far it is from the nearest planet. If it's on the surface of Earth, it weighs (19 kg) x (9.8 m/s^2) = 186.2 newtons.
7 0
3 years ago
Read 2 more answers
Is Time and Light both connected in anyway?​
MissTica

Answer:

It is not connected by any way

8 0
2 years ago
In a thunderstorm, electric charge builds up on the water droplets or ice crystals in a cloud. Thus, the charge can be considere
muminat

Answer:

2.1\cdot 10^{21} electrons

Explanation:

The magnitude of the electric field outside an electrically charged sphere is given by the equation

E=\frac{kQ}{r^2}

where

k is the Coulomb's constant

Q is the charge stored on the sphere

r is the distance (from the centre of the sphere) at which the field is calculated

In this problem, the cloud is assumed to be a  charged sphere, so we have:

E_b=3.00\cdot 10^6 N/C is the maximum electric field strength tolerated by the air before breakdown occurs

r=1.00 km = 1000 m is the radius of the sphere

Re-arranging the equation for Q, we find the maximum charge that can be stored on the cloud:

Q=\frac{Er^2}{k}=\frac{(3.00\cdot 10^6)(1000)^2}{9\cdot 10^9}=333.3 C

Assuming that the cloud is negatively charged, then

Q=-333.3 C

And since the charge of one electron is

e=-1.6\cdot 10^{-19}C

The number of excess electrons on the cloud is

N=\frac{Q}{e}=\frac{-333.3}{-1.6\cdot 10^{-19}}=2.1\cdot 10^{21}

5 0
3 years ago
a coil has n turns enclosing an area of a. in a physics laboratory experiment, the coil is rotated during the time interval δt f
Mrac [35]
The correct answer for the question that is being presented above is this one:

Phi = BAsin(theta) 
<span>1. Phi(i) = BA </span>
<span>2. Phi(f) = 0 </span>
3. EMF = N(phi(i)-phi(f))/deltat

Here are the follow-up questions:

<span>1. What is the total magnitude Phi_initial of the magnetic flux through the coil before it is rotated? </span>
<span>2. What is the magnitude Phi_final of the total magnetic flux through the coil after it is rotated? </span>
<span>3. What is the magnitude of the average emf induced in the coil?</span>
8 0
3 years ago
It took Lilly 7 seconds to ride her bike 35 meters to the end of the block.What was her speed?
Zolol [24]
<h2><em>her average speed was 5 meter p/ second </em></h2><h2><em> 18 kph</em></h2><h2><em>                                     HOPE IT HELPS (◕‿◕✿)                                   </em></h2><h2><em>                                                   SMILE!!</em></h2>
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3 years ago
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