Question

A container of gas has a volume of 3.5 L and a pressure of 0.8 atm. Assuming the temperature remains constant, what volume of gas would result if the pressure was 0.5 atm?
A. 5.6 L
B. 2.2 L
C. 0.2 L
D. 1.8 L

Answer 1

Answer:

The correct answer is option A.

Explanation:

Initial volume of the gas =$V_1=3.5 L$

Final volume of the gas = $V_2=?$

Initial pressure of the gas =$P_1=0.8 atm$

Final volume of the gas = $P_2=0.5 atm$

Using Boyle's law:

$P_1V_1=P_2V_2$

$0.8 atm \times 3.5 L=0.5 atm\times V_2$

$V_2=5.6 L$

Hence,the correct answer is option A.

Answer 2

Answer : The correct option is, (A) 5.6 L

Explanation :

Boyle's Law : It is defined as the pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$

or,

$P_1V_1=P_2V_2$

where,

$P_1$ = initial pressure of gas = 0.8 atm

$P_2$ = final pressure of gas = 0.5 atm

$V_1$ = initial volume of gas = 3.5 L

$V_2$ = final volume of gas = ?

Now put all the given values in the above equation, we get:

$0.8atm\times 3.5L=0.5atm\times V_2$

$V_2=5.6L$

Therefore, the final volume of the gas is 5.6 L.