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inna [77]
3 years ago
8

What element is used in light bulbs as a filament???? help rly need help

Chemistry
1 answer:
frutty [35]3 years ago
6 0
The answer would just be:
<span>Tungsten
</span>hope that this helps you! =)
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Which factor MOST directly affects the flow of ocean currents?w of ocean currents?
Lynna [10]

B)  differences in temperature

Explanation:

The factor that most directly affects the flow of ocean currents is the differences in ocean temperature from one place to another.

Ocean current is the directional movement of the ocean water in its basin.

The main cause of ocean current is differences in temperature.

  • Ocean water on the surface receives direct sunlight.
  • This warms and the surface and decreases their density.
  • When winds blows over them, they cool and sink under their own weight.
  • The less cold water in depths rise to replace them.
  • This exchange of ocean water due to loss and gain of heat cause ocean current.

learn more:

Ocean density brainly.com/question/6760255

#learnwithBrainly

6 0
3 years ago
HURRYYY !!!! What radioactive isotope produces Aluminum-13 by beta decay
fgiga [73]

Answer:

I DONT KNOW SORRY

Explanation:

7 0
3 years ago
Read 2 more answers
A material has a density of 8.9 g/cm^3. You have 3 grams of the substance. How much space does it take up? a. 0.3cm3 b. 3.0 cm3
My name is Ann [436]
D = m/ V

8.9 = 3 / V

V = 3 / 8.9

V = 0.3 cm³

Answer A

hope this helps!
6 0
3 years ago
Read 2 more answers
The ph of a 0.0100 m solution of the sodium salt of a weak acid is 11.00. what is the ka of the acid?
Vitek1552 [10]
The answer is Ka = 1.00x10^-10.
Solution:
When given the pH value of the solution equal to 11, we can compute for pOH as
     pOH = 14 - pH = 14 - 11.00 = 3.00
We solve for the concentration of OH- using the equation
     [OH-] = 10^-pOH = 10^-3 = x

Considering the sodium salt NaA in water, we have the equation
     NaA → Na+ + A- 
hence, [A-] = 0.0100 M

Since HA is a weak acid, then A- must be the conjugate base and we can set up an ICE table for the reaction
                             A- + H2O ⇌ HA + OH-
     Initial             0.0100            0       0
     Change        -x                    +x     +x
     Equilibrium    0.0100-x         x       x

We can now calculate the Kb for A-:
     Kb = [HA][OH-] / [A-] 
           = x<span>²</span> / 0.0100-x
Approximating that x is negligible compared to 0.0100 simplifies the equation to
     Kb = (10^-3)² / 0.0100 = 0.000100 = 1.00x10^-4

We can finally calculate the Ka for HA from the Kb, since we know that Kw = Ka*Kb = 1.0 x 10^-14:
     Ka = Kw / Kb 
           = 1.00x10^-14 / 1.00x10^-4
           = 1.00x10^-10
7 0
3 years ago
Plxzzzzzzzzzzzzzzzzzz
katrin [286]
The correct answers is 1/57
5 0
3 years ago
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