A steady beam of alpha particles (q = + 2e) traveling with constant kinetic energy 14 MeV carries a current of 0.20 µA.

What is the relationship between the electric force and each one of the charges?

Bess [88]

Explanation: Electrostatic force is directly related to the charge of each object. So if the charge of one object is doubled, then the force will become two times greater.

3 0

3 years ago

A gasoline tank has the shape of an inverted right circular cone with base radius 4 meters and height 5 meters. Gasoline is bein

RSB [31]

Answer:

h'=0.25m/s

Explanation:

In order to solve this problem, we need to start by drawing a diagram of the given situation. (See attached image).

So, the problem talks about an inverted circular cone with a given height and radius. The problem also tells us that water is being pumped into the tank at a rate of $8m^{3}/s$ . As you may see, the problem is talking about a rate of volume over time. So we need to relate the volume, with the height of the cone with its radius. This relation is found on the volume of a cone formula:

$V_{cone}=\frac{1}{3} \pi r^{2}h$

notie the volume formula has two unknowns or variables, so we need to relate the radius with the height with an equation we can use to rewrite our volume formula in terms of either the radius or the height. Since in this case the problem wants us to find the rate of change over time of the height of the gasoline tank, we will need to rewrite our formula in terms of the height h.

If we take a look at a cross section of the cone, we can see that we can use similar triangles to find the equation we are looking for. When using similar triangles we get:

$\frac {r}{h}=\frac{4}{5}$

When solving for r, we get:

$r=\frac{4}{5}h$

so we can substitute this into our volume of a cone formula:

$V_{cone}=\frac{1}{3} \pi (\frac{4}{5}h)^{2}h$

which simplifies to:

$V_{cone}=\frac{1}{3} \pi (\frac{16}{25}h^{2})h$

$V_{cone}=\frac{16}{75} \pi h^{3}$

So now we can proceed and find the partial derivative over time of each of the sides of the equation, so we get:

$\frac{dV}{dt}= \frac{16}{75} \pi (3)h^{2} \frac{dh}{dt}$

Which simplifies to:

$\frac{dV}{dt}= \frac{16}{25} \pi h^{2} \frac{dh}{dt}$

So now I can solve the equation for dh/dt (the rate of height over time, the velocity at which height is increasing)

So we get:

$\frac{dh}{dt}= \frac{(dV/dt)(25)}{16 \pi h^{2}}$

Now we can substitute the provided values into our equation. So we get:

$\frac{dh}{dt}= \frac{(8m^{3}/s)(25)}{16 \pi (4m)^{2}}$

so:

$\frac{dh}{dt}=0.25m/s$

3 0

3 years ago

Two electromagnets contain the same types of magnets

Ira Lisetskai [31]

Answer: The first electromagnet has a more powerful current than

the second

Explanation:

Since the two electromagnets contain the same types of magnets and wires. If the magnet In the first moves much faster than the second. Therefore:

The first electromagnet has a more powerful current than the second

Because the induced EMF is proportional to the induced current.

Where the induced EMF depends on the speed of the magnet according to the formula below

EMF = BVL

So, increase in speed of the magnet will cause more powerful induced current and emf

6 0

3 years ago

PLEASE HURRY

Rashid [163]

Answer:

1:knowledge of the structure of DNA

2:an understanding of hemoglobin

4:ground fault circuit interrupters

7:aerogel

Explanation:

7 0

2 years ago

As the drawing illustrates, a siren can be made by blowing a jet of air through 20 equally spaced holes in a rotating disk. The

Aneli [31]

Answer:

ω = 630.2663 = 630[rad/s]

Explanation:

Solution:

- We can tackle this question by simple direct proportion relation between angular speed for the disk to rotate a cycle that constitutes 20 holes. We will use direct relation with number of holes per cycle to compute the revolution per seconds i.e frequency of speed f.

1rev(20 hole) -> 20(cycle)/rev

2006.2(cycle) -> f ?

f = 2006.2/20 = 100.31rev at second

- The relation between angular frequency and angular speed is given by:

ω = 2πf

ω = 2*3.14*100.31

ω = 630.2663 = 630[rad/s]

4 0

3 years ago