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olasank [31]
3 years ago
15

The area of a parallelogram with the height of 6 meters is a hundred twenty six square meters what is the base length of the par

allelogram
Mathematics
2 answers:
Anastaziya [24]3 years ago
6 0
That's easy, it is 126 divided by 6 equals 21 meters. cause the formula is base times height = area so you do the opposite of it which is base = area divide by height
AnnyKZ [126]3 years ago
5 0
Just divide. 120÷6=21. So the Answer is 21. Hoped I helped. :)
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What is his average speed for end the entire trip 280 miles<br> ?
-BARSIC- [3]

Answer:

20mph

Step-by-step explanation:

because when you divide the 280 it goes by 20 mph to get to 280 miles by quarters but in 20s

7 0
2 years ago
Translate the following word phrases to an algebraic expression and simplify: “8 times the difference of 6 times a number and 3”
Ostrovityanka [42]

SOLUTION:

Step 1:

In this question, we are meant to:

Translate the following word phrases to an algebraic expression and simplify:



“8 times the difference of 6 times a number and 3”

Step 2:

Assuming the unknown number be y, we have that:

\begin{gathered} 8\text{ ( 6y - 3 )} \\ =\text{ 48 y - 24} \end{gathered}

CONCLUSION:

The final answer is:

48y\text{ - 24}

3 0
1 year ago
Please help me with this math problem. Only type answer please dont upload files
posledela
3) 3(8b + 3)
4) 57

I’m pretty sure that this is the answer
8 0
3 years ago
This is a 3 part 1 question each part on how to locate the plane and a small explanation report working out the recovery details
sesenic [268]

Third leg.

The crew flies at a speed of 560 mi/h in direction N-20°-E.

The wind has a speed of 35 mi/h and a direction S-10°-E.

We then can draw this as:

We have to add the two vectors to find the actual speed and direction.

We will start by adding the x-coordinate (W-E axis):

\begin{gathered} x=560\cdot\sin (20\degree)+35\cdot\sin (10\degree) \\ x\approx560\cdot0.342+35\cdot0.174 \\ x\approx191.53+6.08 \\ x\approx197.61 \end{gathered}

and the y-coordinate (S-N axis) is:

\begin{gathered} y=560\cdot\cos (20\degree)-35\cdot\cos (10\degree) \\ y\approx560\cdot0.940-35\cdot0.985 \\ y\approx526.23-34.47 \\ y\approx491.76 \end{gathered}

Then, the actual speed vector is v3=(197.61, 491.76).

The starting location for the third leg is R2=(216.66, 167.67) [taken from the previous answer].

Then, we have to calculate the displacement in 20 minutes using the actual speed vector.

We can calculate the movement in each of the axis. For the x-axis:

\begin{gathered} R_{3x}=R_{2x}+v_{3x}\cdot t \\ R_{3x}=216.66+197.61\cdot\frac{1}{3} \\ R_{3x}=216.66+65.87 \\ R_{3x}=282.53 \end{gathered}

NOTE: 20 minutes represents 1/3 of an hour.

We can do the same with the y-coordinate:

\begin{gathered} R_{3y}=R_{2y}+v_{3y}\cdot t \\ R_{3y}=167.67+491.76\cdot\frac{1}{3} \\ R_{3y}=167.67+163.92 \\ R_{3y}=331.59 \end{gathered}

The final position is R3 = (282.53, 331.59).

To find the distance from the origin and direction, we transform the cartesian coordinates of R3 into polar coordinates:

The distance can be calculated as if it was a right triangle:

\begin{gathered} d^2=x^2+y^2_{} \\ d^2=282.53^2+331.59^2 \\ d^2=79823.20+109951.93 \\ d^2=189775.13 \\ d=\sqrt[]{189775.13} \\ d\approx435.63 \end{gathered}

The angle, from E to N, can be calculated as:

\begin{gathered} \tan (\alpha)=\frac{y}{x} \\ \tan (\alpha)=\frac{331.59}{282.53} \\ \tan (\alpha)\approx1.1736 \\ \alpha=\arctan (1.1736) \\ \alpha=49.56\degree \end{gathered}

If we want to express it from N to E, we substract the angle from 90°:

\beta=90\degree-\alpha=90-49.56=40.44\degree

Answer: the final location can be represented with the vector (282.53, 331.59).

1) The distance from the origin is 435.63 miles and

2) the direction is N-40°-E.

7 0
1 year ago
The points ​(​15, 18​) and ​(​35,42) form a proportional relationship. Find the slope of the line through the points. Then use t
Ann [662]

Answer:

6/5

Step-by-step explanation:

(42-18) / (35 - 15)  = 24 / 20  = 6 / 5

8 0
3 years ago
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