A car drives around a curve with radius 400 m at a speed of 32 m/s. The road is banked at 7.0 degree. The mass of the car is 150
1 answer:
Answer:
The magnitude of the centripetal force to make the turn is 3,840 N.
Explanation:
Given;
radius of the cured road, r = 400 m
speed of the car, v = 32 m/s
mass of the car, m = 1500 kg
The magnitude of the centripetal force to make the turn is given as;
where;
Fc is the centripetal force
Therefore, the magnitude of the centripetal force to make the turn is 3,840 N.
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Answer:
Do find the answer in the attachment herein.
Explanation:
From the attached diagram:
I. Activation energy = Activated complex - ∆H(reactants)
Activation energy = 162-140 = 22Kj.
II. ∆H(reaction) = ∆H(products) - ∆H(reactants)
∆H(reaction) = 37 - 140 = -103Kj.
For an uniformly accelerated motion, we can write
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is the acceleration of this motion, which in this problem is the gravitational acceleration, with a negative sign because it points downward, against the direction of the motion; h=0.540 m is the distance covered by the flea, and 
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At the maximum height, the velocity is zero, so
. Therefore we can solve to find :
where
At the maximum height, the velocity is zero, so