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antoniya [11.8K]
3 years ago
8

How much heat do you need to raise the temperature of 150 g of gasoline from -30 degrees C to -15 degrees C? I cannot see the ti

nycurl

Chemistry
2 answers:
Pachacha [2.7K]3 years ago
5 0

Answer:

5.00 kj

Explanation:

I took the test

Nutka1998 [239]3 years ago
3 0
Q = mCpΔT

Cp = 2.22 J/g°C
m = 150 g
ΔT = T(final) - T(initial) = -15°C - (-30°C) = +15°C

q = (150 g)(2.22 J/g°C)(15°C) = 4,995 J
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Usually you would call this a saturated solution. I hope this helps.
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3 years ago
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The microscopes used today are just like the ones used by Leeuwenhoek and Hooke. True or false
Dmitry [639]

Answer:

False

Explanation:

While we do know that A. Leeuwenhoek used a simple microscope that consisted of only 1 lens, Hooke used a compound microscope. Although, after trying a compound microscope, Hooke found out that it strained his eyes and continued to use a simple microscope for his <em>Micrographia</em>.

Thus, we can say that the (compound) microscopes used today are different than the (simple) microscope used by Hooke and Leeuwenhoek.

6 0
2 years ago
Determine the value of the equilibrium constant, Kgoal, for the reaction C(s)+12O2(g)+H2(g)⇌12CH3OH(g)+12CO(g), Kgoal=? by makin
Licemer1 [7]

Answer:

1.71x10²⁷

Explanation:

If we sum 1/2 of (3) + 1/2 of (1):

1/2 (3.) C(s) + 1/2O₂(g) ⇌ CO(g), K₃ = √2.10×10⁴⁷  = 4.58x10²³

1/2 (1)   1/2CO₂(g) + 3/2H₂(g) ⇌ 1/2CH₃OH(g) + 1/2H₂O(g), K₁ = √1.40×10² = 11.8

C(s) + 1/2O₂(g) +<u> 1/2CO₂(g) </u>+<u> 3/2H₂(g</u>) ⇌ 1/2CH₃OH(g) + <u>1/2H₂O(g)</u> + <u>CO(g)</u>

K' = 4.58x10²³ * 11.8 = 5.42x10²⁴

+1/2 (2):

<u>1/2 CO(g)</u> +<u> 1/2H₂O(g)</u> ⇌<u> 1/2CO₂(g)</u> + <u>1/2H₂</u> (g), K = √1.00×10⁵ = 316.2

C(s) + 1/2O₂(g) + H₂(g) ⇌ 1/2 CHO₃H(g) + 1/2CO(g)

K'' = 5.42x10²⁴* 316.2 =

<h3>1.71x10²⁷</h3>

5 0
3 years ago
Which of the following illustrates a longitudinal wave?
monitta

Answer:

figure no. A is right answer.......

7 0
2 years ago
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What concentration of benzoic acid will have a ph of 4.0? (for benzoic acid, pka=4.20)?
aalyn [17]
We are given the molar concentration of an aqueous solution of weak acid and the pH ofthe solution, and we are asked to determine the value of Ka for the acid.
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The equilibrium-constant expression is the equation number (2)
From the measured pH, we can calculate pH as seen in equation (3)
To determine the concentrations of the species involved in the equilibrium, we imagine that thesolution is initially 0.10 M in HCOOH molecules. We then consider the ionization of the acidinto H+ and HCOO-. For each HCOOH molecule that ionizes, one H+ ion and one HCOO- ionare produced in solution. Because the pH measurement indicates that [H+] = 1x 10^-4 M atequilibrium, we can construct the following table as seen in the equation number (4)
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Therefore, 2.58x10^-4 M is the concentration of benzoic acid to have a pH of 4.0

7 0
3 years ago
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