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never [62]
1 year ago
10

7. Interpret Data A company plans to make an electronic device. They need to use an element that has chemical behavior similar t

o that of silicon (Si) and lead (Pb).
The element must have an atomic mass greater than that of sulfur (S), but less than that of cadmium (Cd), Use the periodic table to determine which element the company will use.
Chemistry
1 answer:
Goryan [66]1 year ago
3 0

Germanium (Ge) is an element that has chemical behavior similar to that of silicon (Si) and lead (Pb). As it has an atomic mass greater than that of sulfur (S), but less than that of cadmium (Cd).

<h3>Why does the element of the same group have similar chemical behavior?</h3>

The chemical behavior of elements depends on the number of valence electrons in their outermost shell. Elements placed in the same group have the same number of valence electrons. Therefore, elements placed in the same group of the periodic table have similar chemical properties.

The elements having a similar outer electronic configuration in their atoms are arranged in the same group of the periodic table. These valence electrons are responsible chemical properties and reactivities of the elements.

Therefore, silicon and lead can be replaced by any element belonging to the same group in which Si and Pb are present. So we have germanium and tin. But germanium is the element that has an atomic mass greater than sulfur (S), but less than cadmium (Cd).

Learn more about elements with similar chemical behavior, here:

brainly.com/question/5364617

#SPJ1

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Why is Mg++ smaller than Mg atom?​
Evgen [1.6K]

Answer:

The magnesium ion is much smaller than the magnesium atom because magnesium atom contains more electrons as compared to magnesium ion. Explanation: ... Whereas when an atom tends to lose an electron then it acquires a positive charge and size of the atom tends to increase.

7 0
3 years ago
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Convert 1297 cm to m.
Svet_ta [14]

Answer:

Not sure,12.97(if u get it wrong let me know)

Explanation:

100cm=1m

Then 1297cm=

1297 \100

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3 years ago
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One mole of an ideal gas, CP=3.5R, is compressed adiabatically in a piston/cylinder device from 2 bar and 25 oC to 7 bar. The pr
Luda [366]

Answer:

the entropy change of the gas is ΔS= 2.913 J/K

Explanation:

starting from the first law o thermodynamics for an adiabatic reversible process

ΔU= Q - W

where

ΔU = change in internal energy

Q= heat flow = 0 ( adiabatic)

W = work done by the gas

then

-W=  ΔU

also we know that the ideal compression work Wcom= - W , then Wcom = ΔU. But also for an ideal gas

ΔU= n*cv* (T final - T initial)

where

n=moles of gas

cv= specific heat capacity at constant volume

T final =T₂= final temperature of the gas

T initial =T₁= initial temperature of the gas

and also from an ideal gas

cp- cv = R → cv = 7/2*R - R = 5/2*R

therefore

W com = ΔU = n*cv* (T final - T initial)

for an ideal gas under a reversible adiabatic process ΔS=0 and

ΔS= cp*ln(T₂/T₁) - R* ln (P₂/P₁) =0

therefore

T₂ = T₁* (P₂/P₁)^(R/cp) = T₁* (P₂/P₁)^(R/(7/2R))=  T₁* (P₂/P₁)^(2/7)

replacing values T₁=25°C= 298 K

T₂ =T₁* (P₂/P₁)^(2/7)  = 298 K *(7 bar/2 bar)^(2/7) = 426.25 K

then

W com = ΔU = n*cv* (T₂- T₁)  

and the real compression work is W real = 1.35*Wcom , then

W real = ΔU

W real = 1.35*Wcom = n*cv* (T₃ - T₁)

T₃ = 1.35*Wcom/n*cv + T₁ = 1.35*(T₂- T₁) + T₁ =1.35*T₂ - 0.35*T₁ = 1.35*426.25 K - 0.35 *298 K = 471.14 K

T₃ = 471.14 K

where

T real = T₃  

then the entropy change will be

ΔS= cp*ln(T₃/T₁) - R* ln (P₂/P₁) = 7/2* 8.314 J/mol K *ln(471.14 K /298 K ) - 8.314 J/mol K* ln (7 bar / 2 bar)  = 2.913 J/K

ΔS= 2.913 J/K

5 0
3 years ago
Can someone help me i'm confused
Rashid [163]
Answer: A

Reactants combine to make a larger atom and release a neutron. Only A does that.
7 0
3 years ago
Iodine, I2, is a solid at room temperature but sublimes (converts from a solid into a gas) when warmed. What is the temperature
Finger [1]

Answer:

T = 3.75 K

Explanation:

As we know

PV = nRT

R =8.3144598 J. mol-1. K-1

P = 0.562 atm

V = 83.3 mL

moles in 0.392 g of I2 = 0.392/mass of I2 = 0.392 grams/253.8089 g/mol = 0.0015 moles

Substituting the given values, we get

0.562 atm * 83.3 *10^-3 L = 0.0015 moles * 8.3144598 J. mol-1. K-1 * T

T = 3.75 K

3 0
3 years ago
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