Answer:
Average atomic mass of Cl = 35.48 amu
Average atomic mass of B = 10.8 amu
Average atomic mass of Ag = 107.96 amu
Explanation:
1)
Given data:
Abundance of Cl-35 = 75.8%
Abundance of Cl-37 = 24.2%
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (75.8×35)+(24.2×37) /100
Average atomic mass = 2653 + 895.4 / 100
Average atomic mass = 3548.4 / 100
Average atomic mass = 35.48 amu
2)
Given data:
Abundance of B-10 = 19.8%
Abundance of B-11 = 80.2%
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (19.8×10)+(80.2×11) /100
Average atomic mass = 198 +882.2 / 100
Average atomic mass = 1080.2 / 100
Average atomic mass = 10.8 amu
3)
Given data:
Abundance of Ag-107 = 52%
Abundance of Ag-109 = 48%
Average atomic mass = ?
Solution:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (52×107)+(48×109) /100
Average atomic mass = 5564 +5232 / 100
Average atomic mass = 10796 / 100
Average atomic mass = 107.96 amu
