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2 years ago

Name some radioactive elements.

Chemistry

2 answers:

natulia [17]2 years ago

6 0

Hello there!

Uranium

Protactinium

Radium

Polonium

Actinium

Neptunium

Curium

Einsteinium

Hope it helps

Rainbow [258]2 years ago

5 0

Answer:

Alpha Radiation.

Uranium.

Radium.

Radon.

Polonium.

Actinium.

Protactinium.

Thorium.

Explanation:

Thanks!!!!!

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If winds blow against a mountain from the south, then on which slope would you find the least precipitation?

Aleksandr-060686 [28]

The northern slope will have the least precipitation if winds blow against a mountain from the south.

<h3>What is Slope?</h3>

This is referred to as the degree of steepness on a surface such as rocky areas etc.

When wind blows on the southern part of a mountains, it gets stuck which is why the northern slope have the least precipitation.

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1 year ago

High concentrations of ammonia (NH3), nitrite ion, and nitrate ion in water can kill fish. Lethal concentrations of these specie

kykrilka [37]

Explanation:

It is known that molality is the number of moles present in kg of solution.

Mathematically, Molality = $\frac{\text{no. of moles of solute}}{\text{mass of solvent in Kg}}$

The given data is as follows.

Molar mass of ammonia = 17 g/mol

Concentration = 1.002 mg/L = $\frac{0.001002 g/L}{17 g/mol}$

= $5.89 \times 10^{-4}$ mol/L

Also, density = $\frac{1 g}{mL}$ = 1 kg/L

Therefore, molality will be calculated as follows.

Molality = $\frac{5.89 \times 10^{-4} mol/L}{1 kg/L}$

= $5.89 \times 10^{-4} mol/kg$

And,

Molar mass of nitrite = 46 g/mol

Concentration = 0.387 mg/L = $\frac{0.000412 g/L}{46 g/mol}$

= $8.956 \times 10^{-6}$ mol/L

And, density = $\frac{1 g}{mL}$ = 1 kg/L

Hence, molality = $\frac{8.956 \times 10^{-6} mol/L}{1 kg/L}$

= $8.956 \times 10^{-6}$ mol/kg

Now, Molar mass of nitarte = 62 g/mol

Concentration = 1352.2 mg/L

= $\frac{1.3522 g/L}{62 g/mol}$

= 0.02181 mol/L

Also, density = $\frac{1 g}{mL}$ = 1 kg/L

Hence, molality will be calculated as follows.

Molality = $\frac{0.02181 mol/L}{1 kg/L}$

= 0.02181 mol/kg

Therefore, molality of given species is $5.89 \times 10^{-4} mol/kg$ for ammonia, $8.956 \times 10^{-6}$ mol/kg for nitrite, and 0.02181 mol/kg for nitrate ion.

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3 years ago

A student requires 2.00 L of 0.100 M NH4NO3 from a 1.75 M NH4NO3 stock solution. What is the correct way to get the solution?

Sonbull [250]

Answer: Measure 114 mL of the 1.75 M solution, and dilute it to 2.00 L.

Explanation:

The number of moles in the solution will remain same on dilution and thus according to Molarity Equation:

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$M_1$ = molarity of first solution

$V_1$ = Volume of first solution

$M_2$ = molarity of second solution

$V_2$ = Volume of second solution

$0.1\times 2.00L=1.75M\times V_2$

$V_2=0.114L=114ml$

Thus 114 ml of 1.75 M solution is taken and the volume is diluted to 2.0 L to make 0.100 M solution.

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3 years ago

Calculate the number of ammonia molecules in 3.9 g.

disa [49]

•3.9g of ammonia
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1st you have to covert grams to moles by dividing the mass of ammonia with the molar mass:

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Then convert the moles to molecules by multiplying it with Avogadro’s number:

Avogadro’s number: 6.022 x 10^23

0.22900763mols x (6.022 x 10^23 molecs/mol)
= 1.38 x 10^23 molecules

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3 years ago

Name some radioactive elements.​

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