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3 years ago

How does solar energy compare to wind energy and fossil fuels?

1 answer:

6 0

All of them are a source of getting energy but solar and wind energy are a more beneficial way of producing the energy we need.

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What's the answer to the question in the picture??

Burka [1]

Answer:

Explanation:

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3 years ago

A scientist is investigating the rate of cellular respiration when a person is exercising and when at rest. How would the amount

matrenka [14]

During exercise, your body needs more energy, which means your tissues consume more oxygen than they do at rest. Consuming more oxygen means you will also produce more carbon dioxide because your metabolic rate is elevated.

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2 years ago

Can anyone help giving 5 stars

Assoli18 [71]

Answer:

drawing b is correct

Explanation:

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friend,please vote my answer 5 star

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2 years ago

What is the relationship between a calorie and a<br> joule?

Mandarinka [93]

One calorie is equal to approximately 4.2 joules.

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2 years ago

Pressure cookers allow food to cook faster because the higher pressure inside the pressure cooker increases the boiling temperat

KonstantinChe [14]

Answer:

$\boxed{\text{139 $\, ^{\circ}$C}}$

Explanation:

The question is asking, "At what temperature does the vapour pressure of water equal 3.4 atm?"

To answer this question, we can use the Clausius-Clapeyron equation:

$\ln \left (\dfrac{p_{2}}{p_{1}} \right) = \dfrac{\Delta_{\text{vap}}H}{R} \left(\dfrac{1 }{ T_{1} } - \dfrac{1}{T_{2}} \right)$

Data:

p₁ = 1 atm; T₁ = 373.15C

p₂ = 3.4atm; T₂ = ?

R = 8.314 J·K⁻¹mol⁻¹

$\Delta_{\text{vap}}H = \text{39.67 kJ//mol}$

(The enthalpy of vaporization changes with temperature. Your value may differ from the one I chose.)

Calculation:

$\begin{array}{rcl}\ln \left (\dfrac{p_{2}}{p_{1}} \right)& = & \dfrac{\Delta_{\text{vap}}H}{R} \left( \dfrac{1}{T_{1}} - \dfrac{1}{T_{2}} \right)\\\\\ln \left (\dfrac{3.4}{1} \right)& = & \dfrac{39670}{8.314} \left(\dfrac{1 }{ 373.15 } - \dfrac{1}{T_{2}} \right)\\\\\ln3.4 & = & 4771 \left(\dfrac{1 }{ 373.15 } - \dfrac{1}{T_{2}} \right)\\\\1.224 & = & 12.78 - \dfrac{4771}{T_{2}}\\\\\dfrac{4771}{T_{2}} & = & 11.56\\\\\end{array}$

$T_{2} & = & \dfrac{4771}{11.56} = \text{412.6 K} = \textbf{139 $\, ^{\circ}$C}\\\\\text{The maximum temperature is } \boxed{\textbf{139 $\, ^{\circ}$C}}$

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3 years ago