Answer:
1,600 to 1,700 kilocalories per day
Explanation:
Volume doesn't depend on what the substance is, only on how much of it there is.
Answer:
The mass of the solution is 120 g.
Explanation:
The mass of the solution is given by:

Where:
: is the mass of the solution
: is the mass of the solvent
: is the mass of the solute
In the solution, the solvent is the majority compound (in mass) and the solute is the minority (in mass), so the solvent is the water and the solute is sodium chloride.
Hence, the mass of the solution is:
I hope it helps you!
Answer:
a) 



b) 
Explanation:
From the exercise we got the ball's equation of position:

a) To find the average velocity at the given time we need to use the following formula:

Being said that, we need to find the ball's position at t=2, t=2.5, t=2.1, t=2.01, t=2.001



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

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

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

b) To find the instantaneous velocity we need to derivate the equation


Answer:
<h2>Radiation</h2>
Explanation:
<h3>Greetings !</h3>
The Sun reaches us by propagating through the vacuum of space. Sunlight reaches the Earth in about 8 minutes and 20 seconds. When this energy reaches the Earth's atmosphere, both conduction and convection play key roles to scatter it throughout the planet.