Question

A circular loop of wire has radius of 9.50 cmcm. A sinusoidal electromagnetic plane wave traveling in air passes through the loop, with the direction of the magnetic field of the wave perpendicular to the plane of the loop. The intensity of the wave at the location of the loop is 0.0215 W/m2W/m2, and the wavelength of the wave is 6.90 mm.What is the maximum emf induced in the loop?
Express your answer with the appropriate units.

Answer 1

Answer:

The induced emf  is  $\epsilon = 0.1041 \ V$  

Explanation:

From the question we are told that

   The  radius of the circular loop is  $r = 9.50 \ cm = 0.095 \ m$

     The  intensity of the wave is  $I = 0.0215 \ W/m^2$

      The wavelength is  $\lambda = 6.90\ m$

Generally the intensity is mathematically represented as

         $I = \frac{ c * B^2 }{ 2 * \mu_o }$

Here  $\mu_o$ is the permeability of free space with value  

         $\mu_o = 4 \pi *10^{-7} N/A^2$

B is the magnetic field which can be mathematically represented from the equation as

          $B = \sqrt{ \frac{ 2 * \mu_o * I }{ c} }$

substituting values

          $B = \sqrt{ \frac{ 2 * 4\pi *10^{-7} * 0.0215 }{ 3.0*10^{8}} }$

          $B = 1.342 *10^{-8} \ T$

The  area is mathematically represented as

       $A = \pi r^2$

substituting values

       $A = 3.142 * (0.095)^2$

       $A = 0.0284$

The angular velocity is mathematically represented as

        $w = 2 * \pi * \frac{c}{\lambda }$

substituting values          

       $w = 2 * 3.142 * \frac{3.0*10^{8}}{ 6.90 }$  

        $w = 2.732 *10^{8} rad \ s^{-1}$  

Generally the induced emf is mathematically represented as

        $\epsilon = N * B * A * w * sin (wt )$

At maximum induced emf  $sin (wt) = 1$

    So

         $\epsilon = N * B * A * w$

substituting values

         $\epsilon = 1 * 1.342 *10^{-8} * 0.0284 *2.732 *10^{8}$  

         $\epsilon = 0.1041 \ V$