(Multiple choice) Of the following species, which is most likely to be oxidized?

Chemistry

1 answer:

ollegr [7]1 year ago

8 0

An element that is oxidized is one that loses electrons, losing electrons increases its oxidation state. Now, the more electrons there are in the last energy level of the element, that is, valence electrons, the easier it will be for this element to lose them. We can identify valence electrons in the periodic table, the group to which the element belongs indicates how many valence electrons it has. Let's see what the oxidation state of the elements is:

F:7

Li:1

N:5

Be:2

O:6

We see that Lithium is the one with the fewest valence electrons, it has only one valence electron, so this will be the element that is most likely to be oxidized.

Answer: 2. Li

You might be interested in

Write the structure of the aldol condensation-dehydration product that you synthesized. Using this structure, analyze the NMR sp

STALIN [3.7K]

Answer:

Please find the solution in the attached file.

Explanation:

8 0

2 years ago

The half-life of radioactive substance is 2.5 minutes. what fraction of the origional radioactive remains after 10 mins

saul85 [17]

The answer is 1/16.

Half-life is the time required for the amount of a sample to half its value.
To calculate this, we will use the following formulas:
1. $(1/2)^{n} = x$ ,
where:
n - a number of half-lives
x - a remained fraction of a sample

2. $t_{1/2} = \frac{t}{n}$
where:
 $t_{1/2}$ - half-life
t - total time elapsed
n - a number of half-lives

So, we know:
t = 10 min
 $t_{1/2}$ = 2.5 min

We need:
n = ?
x = ?

We could first use the second equation to calculate n:
If:
$t_{1/2} = \frac{t}{n}$ ,
Then:
$n = \frac{t}{ t_{1/2} }$
⇒ $n = \frac{10 min}{2.5 min}$
⇒ $n=4$ 

Now we can use the first equation to calculate the remained fraction of the sample.
 $(1/2)^{n} = x$
⇒ $x=(1/2)^4$
⇒ $x= \frac{1}{16}$