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1 year ago

(Multiple choice) Of the following species, which is most likely to be oxidized?

Chemistry

1 answer:

ollegr [7]1 year ago

8 0

An element that is oxidized is one that loses electrons, losing electrons increases its oxidation state. Now, the more electrons there are in the last energy level of the element, that is, valence electrons, the easier it will be for this element to lose them. We can identify valence electrons in the periodic table, the group to which the element belongs indicates how many valence electrons it has. Let's see what the oxidation state of the elements is:

F:7

Li:1

N:5

Be:2

O:6

We see that Lithium is the one with the fewest valence electrons, it has only one valence electron, so this will be the element that is most likely to be oxidized.

Answer: 2. Li

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Explain why two thin sweaters feel warmer then one thick sweater

jeyben [28]

Answer:

Two slender woolen sweaters are hotter than a thick woolen sweater in light of the fact that there is a layer of air between them that doesn't permit our body warmth to get away yet it likewise it doesn't retains heat from the climate and fleece is additionally a protector that itself doesn't permit our body warmth to get away

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3 years ago

A container has a volume of 2.79 L and a pressure of 5.97 atm. If the pressure changes to 1460 mm Hg, what is the container’s ne

maw [93]

Answer:

8.68 L is the new volume

Explanation:

You use Boyle's law for this.

$P_{1}V_{1}=P_{2}V_{2}$

$P_{1}$ = first pressure

$P_{2}$ = second pressure

$V_{1}$ = first volume

$V_{2}$ = second volume

Convert pressure from atm to mmHg (use same units):

5.97 x 760 = 4537.2 -> 4.54 x 10³

...maintain 3 significant figures in calculation, and round as needed...

(4.54 x 10³ mmHg)(2.79 L) = (1460 mmHg)( $V_{2}$ )

(4.54 x 10³ mmHg)(2.79 L) / (1460 mmHg) = $V_{2}$ = 8.68 L

Hope this helps :)

5 0

2 years ago

Understanding the theory of plate tectonics can help people better understand Earth's movements. How can knowledge of plate tect

Anettt [7]

The knowledge of plate tectonics help people living in areas prone to earthquakes and volcanic eruptions can help by knowing the chances of the earthquake or volcanic eruption

4 0

2 years ago

A certain substance X has a normal freezing point of 5.6 °C and a molal freezing point depression constant Kf-7.78 °C-kg·mol-1.

Harrizon [31]

Answer:

27.60 g urea

Explanation:

The freezing-point depression is expressed by the formula:

ΔT= Kf * m

In this case,

ΔT = 5.6 - (-0.9) = 6.5 °C

Kf = 7.78 °C kg·mol⁻¹

m is the molality of the urea solution in X (mol urea/kg of X)

First we calculate the molality:

6.5 °C = 7.78 °C kg·mol⁻¹ * m

m = 0.84 m

Now we calculate the moles of urea that were dissolved:

550 g X ⇒ 550 / 1000 = 0.550 kg X

0.84 m = mol Urea / 0.550 kg X

mol Urea = 0.46 mol

Finally we calculate the mass of urea, using its molecular weight:

0.46 mol * 60.06 g/mol = 27.60 g urea

7 0

3 years ago

Use the equation editor or "Insert Chemistry - WIRIS editor" to write the balanced molecular chemical equation for the reaction

11Alexandr11 [23.1K]

Answer:

Balanced equation:

$Pb(NO_{3})_{2}(aq)+K_{2}CO_{3}(aq)\rightarrow PbCO_{3}(s)+2KNO_{3}(aq)$

Explanation:

The chemical reaction between Lead(II) Nitrate and potassium carbonate is as follows.

$Lead(II)Nitrate+Potassium\,carbonate \rightarrow Lead(III)\,\,carbonate+Potassium\,nitrate$

$Pb(NO_{3})_{2}(aq)+K_{2}CO_{3}(aq)\rightarrow PbCO_{3}(s)+2KNO_{3}(aq)$

Ionic equation:

$Pb^{2+}(aq)+2NO_{3}^{-}(aq)+2K^{+}(aq)+CO_{3}^{2-}(aq)\Leftrightarrow PbCO_{3}(s)+K^{+}(aq)+2NO_{3}^{-}$

Cancel the same ions on the both sides of the reaction.

The net ionic equation is as follows.

$Pb^{2+}(aq)+CO_{3}^{2-}(aq)\Leftrightarrow PbCO_{3}(s)$

4 0

3 years ago