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Sav [38]
1 year ago
13

(Multiple choice) Of the following species, which is most likely to be oxidized?

Chemistry
1 answer:
ollegr [7]1 year ago
8 0

An element that is oxidized is one that loses electrons, losing electrons increases its oxidation state. Now, the more electrons there are in the last energy level of the element, that is, valence electrons, the easier it will be for this element to lose them. We can identify valence electrons in the periodic table, the group to which the element belongs indicates how many valence electrons it has. Let's see what the oxidation state of the elements is:

F:7

Li:1

N:5

Be:2

O:6

We see that Lithium is the one with the fewest valence electrons, it has only one valence electron, so this will be the element that is most likely to be oxidized.

Answer: 2. Li

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2 years ago
What quantity of energy, in joules, is required to raise the temperature of 425 g of tin from room temperature, 25.0 °C, to its
Rama09 [41]

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Total energy required to raise the temperature of 425 g of tin from 298.15 K to 505.05 K and to melt the tin at 505.05 K is 45.249 kiloJoules.

Explanation:

Mass of the tin ,m= 425 g

Heat capacity of the tin ,c= 0.227 J/g K

Initial temperature of the tin ,T_1= 25.0 °C = 298.15 K

Final temperature of the tin, T_2= 231.9 °C = 505.05 K

Let the heat required to change the temperature of tin from 298.15 K to 505.05 K be Q.

Q=mc\times (T_2-T_1)

=425 g\times 0.227 J/g K\times (505.05K - 298.15 K)=19,960.68 J=19.961 kJ

Heat required to melt tin at 505.05 K be Q'

The heat of fusion of tin metal =\Delta H_{fus}=59.2 J/g

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Total energy required to raise the temperature of 425 g of tin from 298.15 K to 505.05 K and to melt the tin at 505.05 K is:

= Q+Q' =  19.961 kJ + 25.288 kJ = 45.249 kJ

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