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3 years ago

Which elements are used for artistic objects

Chemistry

2 answers:

JulijaS [17]3 years ago

7 0

Color, Line, Texture, Space, form, and value

andrew11 [14]3 years ago

6 0

The elements used for artistic objects are components like color, form, line, shape, space, texture, and value.

<u>Explanation:</u>

They forms the basic building blocks of art. A two-dimensional painting or three-dimensional sculpture are decided by the artist. Line, shape, form may encloses volume a such as cube, cylinder, sphere, pyramid.

Value defines the shades of the colors. Spaces are defined the depthness. Colour made up hue having the name of colour value being the darkness or brightness of the colour. Intensity describes the quality of purity and brightness .Texture describes how things appear or feel touched.

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When aluminium and chlorine compared , which has smaller atomic size ? Why ?

Zielflug [23.3K]

Chlorine has a smaller atomic size.
Explanation: As you move towards right of the periodic table, the atomic size decreases. This is because the number of protons is increasing towards the right of the periodic table, which applies a greater inward force on the electrons. that is why the elements on the right of the periodic table have a smaller atomic size when compared to the elements on the left. Since chlorine is on the right side of aluminium, it has a smaller atomic size.

7 0

2 years ago

Read 2 more answers

At constant pressure, which of these systems do work on the surroundings? A ( s ) + B ( s ) ⟶ C ( g ) A(s)+B(s)⟶C(g) 2 A ( g ) +

Tju [1.3M]

Correct question:

At constant pressure, which of these systems do work on the surroundings?

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

(d) 2 A ( g ) + 2 B ( g ) ⟶ 3 C ( g )

Answer:

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

Explanation:

Work done by a system on the surroundings at a constant pressure is given as;

W = -PΔV

Where;

ΔV is gas expansion, that is final volume of the gas minus initial volume of the gas must be greater than zero.

Part (a)

A ( s ) + B ( s ) ⟶ C ( g )

ΔV = 1 - (0) = 1 (expansion)

Part (b)

2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

ΔV = 5 - ( 2+ 2) = 1 (expansion)

Part (c)

A ( g ) + B ( g ) ⟶ C ( g )

ΔV = 1 - ( 1 + 1) = -1 (compression)

Part (d)

2 A ( g ) + 2 B ( g ) ⟶ 3 C ( g )

ΔV = 3 - ( 4) = -1 (compression)

Thus, systems where there is gas expansion are in part (a) and part (b). The correct answers are:

(a) A ( s ) + B ( s ) ⟶ C ( g )

(b) 2 A ( g ) + 2 B ( g ) ⟶ 5 C ( g )

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3 years ago

All of the following are true regarding alcoholic fermentation, except that alcoholic fermentation

guapka [62]

<span>A. produces as much energy as cell respiration.</span>

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3 years ago

A silicon wafer with dimensions 15.00 cm x 15.00 cm x 0.0400 cm

Oxana [17]

The silicon wafer contains 20.96 g of silicon.

The mole of a substance is related to its mass and molar mass by the following equation:

<h3>Mole = mass / molar mass ....... (1)</h3>

Making mass the subject of the above equation, we have

<h3>Mass = mole × molar mass ..... (2)</h3>

With the above formula (i.e equation 2), we can obtain the mass of silicon in the wafer as follow:

Mole silicon = 0.746 mole

Molar mass of silicon = 28.09 g/mol

<h3>Mass of silicon =? </h3>

Mass = mole × molar mass

Mass = 0.746 × 28.09

<h3>Mass of silicon = 20.96 g</h3>

Therefore, the mass of silicon in the wafer is 20.96 g

Learn more: brainly.com/question/24639749

3 0

2 years ago

Express the rate of the reaction in terms of the change in concentration of each of the reactants and products.

weeeeeb [17]

Answer:

c. rate=−1/2Δ[HBr]/Δt=Δ[H2]/Δt=Δ[Br2]/Δt

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

$2HBr(g)\rightarrow H_2(g)+Br_2(g)$

Thus, the rate is given as:

$rate=-\frac{1}{2} \frac{\Delta [HBr]}{\Delta t}=\frac{\Delta [Br_2]}{\Delta t} =\frac{\Delta [H_2]}{\Delta t}$

It is necessary to remember that each concentration to time interval is divided into the stoichiometric coefficient, that is why HBr has a 1/2. Moreover, the concentration HBr is negative since it is a reactant and it has a negative rate due to its consumption.

Therefore, the answer is:

c. rate=−1/2Δ[HBr]/Δt=Δ[H2]/Δt=Δ[Br2]/Δt

Best regards.

4 0

3 years ago