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sladkih [1.3K]
3 years ago
10

If it requires 4.0 J of work to stretch a particular spring by 2.0 cm from its equilibrium length, how much more work will be re

quired to stretch it an additional 4.0 cm?
Physics
1 answer:
ch4aika [34]3 years ago
3 0

Answer:

16J

Explanation:

From hookes law

The work done in a spring is given as W =1/2ke^2

Given that the force constant (k) is constant in the spring material

We have that 2W = e^2

Let W1 = 4J e1= 2cm e2 = 4cm

Let W2 be the work required to stretch it an additional 4cm

W1/ W2 = e1^2/e2^2

W2 = W1* e2^2 / e1^2

= 4* 4^2 /2^2

=4× 16 / 4

= 16J

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Answer:

Yes, it is very helpful.

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which of the following statements best explains how consumers determine growth in technological areas
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Using energy considerations, calculate the average force (in N) a 67.0 kg sprinter exerts backward on the track to accelerate fr
Illusion [34]

Answer:

F_{sprinter}=110.4N

Explanation:

Given data

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From work-energy theorem we know that the work done equals the change in kinetic energy

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And

W=F_{total}.d

So

W=1/2mv_{f}^2-1/2mv_{i}^2\\F_{total}=\frac{1/2mv_{f}^2-1/2mv_{i}^2}{d} \\F_{total}=\frac{1/2(67.0kg)(8.00m/s)^2-1/2(67.0kg)(2.00m/s)^2}{25.0m} \\F_{total}=80.4N

and we know that the force the sprinter exerted Fsprinter the force of the headwind Fwind=30.0N

So

F_{sprinter}=F_{total}+F_{wind}\\F_{sprinter}=80.4N+30N\\F_{sprinter}=110.4N  

7 0
3 years ago
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Answer:

15N

Explanation:

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8 0
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3 years ago
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