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lukranit [14]
1 year ago
9

The coefficient of kinetic friction between an object and the surface upon which it is sliding is 0. 10. The mass of the object

is 8. 0 kg. What is the force of friction?.
Physics
1 answer:
lilavasa [31]1 year ago
4 0

The force of friction is 78.4 N

What is force of friction?

Frictional force is the force created when two surfaces come into contact and slide against each other. it is given by the equation:

F_{f} = μ * F_{n}

where,

F_{f} = force of friction

μ = coefficient of friction

F_{n} = normal force

Given,

μ = 0.10,  m = 8.0 kg

We know,

F_{n} = mg

F_{n} = 8.0 * 9.8\\\\ F_{n} = 78.4 N

Subsituing the values in equation:

F_{f} = μ * F_{n}

F_{f} = 0.10 * 78.4 \\\\F_{f} = 7.84 N

The force of friction is 78.4 N.

To know more about force of friction, check out:

brainly.com/question/24386803

#SPJ4

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3 years ago
How much force does a soccer goalie
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Answer:

2 N

Explanation:

From the question, it's given that

Mass m = 0.2 kg

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3 years ago
A straight wire lies along the y-axis initially carrying a current of 10 A in the positive y-direction. The current decreases an
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Answer:

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The magnetic field due to straight wire is into the square coil.

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8 0
3 years ago
The magnetic field in a cyclotron is 1.25 T, and the maximum orbital radius of the circulating protons is 0.40 m. (a) What is th
Darya [45]

Answer:

1.92 x 10⁻¹²J

Explanation:

The magnetic force from the magnetic field gives the circulating protons gives the particle the necessary centripetal acceleration to keep it orbiting round the circular path. And from Newton's second law of motion, the force(F) is equal to the product of the mass(m) of the proton and the centripetal acceleration(a). i.e

F = ma

Where;

a = \frac{v^2}{r}             [v = linear velocity, r = radius of circular path]

=> F = m\frac{v^2}{r}           ------------(i)

We also know that the magnitude of this magnetic force experienced by the moving charge (proton) in a magnetic field is given by;

F = q v B sin θ       ----------(ii)

Where;

q = charge of the particle

v = velocity of the particle

B = magnetic field

θ = the angle between the velocity and the magnetic field.

Combining equations (i) and (ii) gives

m\frac{v^2}{r} = q v B sin θ           [θ = 90° since the proton is orbiting at the maximum orbital radius]

=> m\frac{v^2}{r} = q v B sin 90°

=> m\frac{v^2}{r} = q v B

Divide both side by v;

=> m\frac{v}{r} = qB

Make v subject of the formula

v = \frac{qBr}{m}

From the question;

B = 1.25T

m = mass of proton = 1.67 x 10⁻²⁷kg

r = 0.40m

q = charge of a proton = 1.6 x 10⁻¹⁹C

Substitute these values into equation(iii) as follows;

v = \frac{(1.6*10^{-19})(1.25)(0.4)}{(1.67*10^{-27})}

v = 4.79 x 10⁷m/s

Now, the kinetic energy, K, is given by;

K = \frac{1}{2}mv²

m = mass of proton

v = velocity of the proton as calculated above

K = \frac{1}{2}(1.67*10^{-27} * (4.79 * 10^7)^2 )

K = 1.92 x 10⁻¹²J

The kinetic energy is 1.92 x 10⁻¹²J

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3 years ago
The world's most powerful laser is the LFEX laser in Japan. It can produce a 2 petawatt(2×10^15W) laser pulse that last for 1 ps
kogti [31]

Answer:

2.82942\times 10^{24}\ W\m^2

Explanation:

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r = Radius of spot = \frac{d}{2}=\frac{30}{2}=15\ mu m

P = Power of the laser = 2\times 10^{15}\ W

A = Area = \pi r^2

Intensity is given by

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The light intensity within this spot is 2.82942\times 10^{24}\ W/m^2

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