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SCORPION-xisa [38]
3 years ago
13

Five difference between elastic collision and inelastic collision?​

Physics
1 answer:
olga_2 [115]3 years ago
8 0

Answer:

Elastic Collision

Inelastic Collision

The total kinetic energy is conserved. The total kinetic energy of the bodies at the beginning and the end of the collision is different.

Momentum does not change. Momentum changes.

No conversion of energy takes place. Kinetic energy is changed into other energy such as sound or heat energy.

Highly unlikely in the real world as there is almost always a change in energy. This is the normal form of collision in the real world.

An example of this can be swinging balls or a spacecraft flying near a planet but not getting affected by its gravity in the end.

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Potassium is a crucial element for the healthy operation of the human
Degger [83]

Answer:

1

  The mass of the Potassium-40 is  m_{40}} = 2.88*10^{-6} kg

2

  The Dose per year in Sieverts is   Dose_s = 26.4 *10^{-10}

Explanation:

From the question we are told that

   The isotopes of potassium in the body are Potassium-39, Potassium-40, and Potassium- 41

    Their abundance is 93.26%, 0.012% and 6.728%

   The mass of potassium contained in human body is  m = 3.0 g = \frac{3}{1000} = 0.0003 \ kg per kg of the body

    The mass of the first body is  m_1 = 80 \ kg

Now the mass of  potassium  in this body is mathematically evaluated as

       m_p =  m * m_1

substituting value

       m_p =  80  * 0.0003

      m_p  =0.024 kg

The amount of Potassium-40 present  is mathematically evaluated as

      m_{40}} =0.012% * 0.024

      m_{40}} = \frac{0.012}{100}  * 0.024

      m_{40}} = 2.88*10^{-6} kg

The dose of energy absorbed per year is mathematically represented as

          Dose  = \frac{E}{m_1}

Where E is the energy absorbed which is given as E = 1.10 MeV = 1.10 * 10^6 * 1.602*10^{-19}

    Substituting value

            Dose  = \frac{ 1.10 * 10^6 * 1.602*10^{-19}}{80}

            Dose  = 22*10^{-10} J/kg

The Dose in Sieverts is evaluated as

       Dose_s = REB * Dose

       Dose_s = 1.2 * 22*10^{-10}

       Dose_s = 26.4 *10^{-10}

             

3 0
3 years ago
If an electronin an electron beam experiences a downward force of 2.0x10^-14N while traveling in a magnetic field of 8.3x10^-2T
Anni [7]

Answer:

Explanation:

Given that,

Force is downward I.e negative y-axis

F = -2 × 10^-14 •j N

Magnetic field is westward, +x direction

B = 8.3 × 10^-2 •i T

Charge of an electron

q = 1.6 × 10^-19C

Velocity and it direction?

Force in a magnetic field is given as

F = q(V×B)

Angle between V and B is 270, check attachment

The cross product of velocity and magnetic field

F =qVB•Sin270

2 × 10^-14 = 1.6 × 10^-19 × V × 8.3 × 10^-2

Then,

v = 2 × 10^-14 / (1.6 × 10^-19 × 8.3 × 10^-2)

v = 1.51 × 10^6 m/s

Direction of the force

Let x be the direction of v

-F•j = v•x × B•i

From cross product

We know that

i×j = k, j×i = -k

j×k =i, k×j = -i

k×i = j, i×k = -j OR -k×i = -j

Comparing -k×i = -j to given problem

We notice that

-F•j = q ( -V•k × B×i)

So, the direction of V is negative z- direction

V = -1.51 × 10^6 •k m/s

6 0
3 years ago
for much of the year this desert is hot dry and windy.What type of plant would you most expect to survive in this climate
abruzzese [7]
I think the answer is cactus
7 0
3 years ago
How do scientists measure the amount of carbon dioxide in the atmosphere for dates prior to the 1955?
Debora [2.8K]

The scientists measured the amount of carbon dioxide in the atmosphere for dates prior to 1955, From air bubbles in glacial ice cores.

Almost 412 parts per million (ppm) of carbon dioxide are currently present in the Earth's atmosphere, and that number is increasing. This indicates an 11 per cent increase since 2000, when the concentration was close to 370 ppm, and a 47 per cent increase since the start of the Industrial Age when the concentration was close to 280 ppm. Most of the time, scientists do not consider Carbon dioxide as a percentage of the earth's atmosphere. It helps to picture a million equal pieces of an atmospheric gas sample.

Learn more about carbon dioxide here:

brainly.com/question/3049557

#SPJ4

6 0
1 year ago
During a race, a runner runs at a speed of 6 m/s. 2 seconds later, she is running at a speed of 10 m/s. What is the runner’s acc
igor_vitrenko [27]
Remember what acceleration is? It's how fast the speed is changing over a period of time.

a =  \frac{dv}{dt}

So in dt = 2 secs, she sped up from 6 to 10 m/s and so dv = (10-6) m/s.

Now that you know dv and dt, you can calculate the acceleration a!
5 0
3 years ago
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