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3 years ago

Five difference between elastic collision and inelastic collision?

Physics

1 answer:

olga_2 [115]3 years ago

8 0

Answer:

Elastic Collision

Inelastic Collision

The total kinetic energy is conserved. The total kinetic energy of the bodies at the beginning and the end of the collision is different.

Momentum does not change. Momentum changes.

No conversion of energy takes place. Kinetic energy is changed into other energy such as sound or heat energy.

Highly unlikely in the real world as there is almost always a change in energy. This is the normal form of collision in the real world.

An example of this can be swinging balls or a spacecraft flying near a planet but not getting affected by its gravity in the end.

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A series of pulses, each of amplitude 0.1 m, is sent down a string that is attached to a post at one end. The pulses are reflect

AleksAgata [21]

Answer:

A_resulting = 0.2 m

Explanation:

Let's analyze the impact of the pulse with the pole, this is a fixed obstacle that does not move therefore by the law of action and reluctant, the force that the pole applies on the rope is of equal magnitude to the force of the rope on the pole (pulse), but opposite directional, so the reflected pulse reverses its direction and sense.

With this information we analyze a point on the string where the incident pulse is and each reflected with an amplitude A = 0.1 m, the resulting is

A_res = 2A

A_resultant = 2 .01

A_resulting = 0.2 m

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3 years ago

A solid cylinder is released from the top of an inclined plane of height 0.81 m. From what height, in meters, on the incline sho

Jlenok [28]

Answer:

same 0.81m

Explanation:

in this problem if we assume there no resistance of any sort. and we apply the energy conservation

change in Potential energy = change in kinetic energy

mgh = 0.5mv^2

gh = 0.5v^2

the above relation suggests that the speed at the bottom is only depending on the height it is released from not on the shape, mass or radius.

so at the bottom

put h = 0.81m

9.81 * 0.81 * 2 = v^2

v=3.99 m/s

both CYLINDER and SPHERE will have same velocity at the bottom if released from the same height irrespective of shape and size

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3 years ago

If a plane is flying level at 910 km/h and the banking angle is not to exceed 50 ∘, what's the minimum curvature radius for the

hoa [83]

Answer:

5.5 km

Explanation:

First, we convert the distance from km/h to m/s

910 * 1000/3600

= 252.78 m/s

Now, we use the formula v²/r = gtanθ to get our needed radius

making r the subject of the formula, we have

r = v²/gtanθ, where

r = radius of curvature needed

g = acceleration due to gravity

θ = angle of banking

r = 252.78² / (9.8 * tan 50)

r = 63897.73 / (9.8 * 1.19)

r = 63897.73 / 11.662

r = 5479 m or 5.5 km

Thus, we conclude that the minimum curvature radius needed for the turn is 5.5 km

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3 years ago

What is the Genetic Modification Process?<br><br> Brainlyist for the best answer

Dovator [93]

Answer:

Production of GMOs is a multistage process which can be summarized as follows:

1. identification of the gene interest;

2. isolation of the gene of interest;

3. amplifying the gene to produce many copies;

4. associating the gene with an appropriate promoter and poly A sequence and insertion into plasmids;

5. multiplying the plasmid in bacteria and recovering the cloned construct for injection;

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3 years ago

Read 2 more answers

The electric field of a sinusoidal electromagnetic wave obeys the equation E=(375V/m)cos[(1.99×107rad/m)x+(5.97×1015rad/s)t].a.

andrey2020 [161]

Answer:

A) max = Eo = 375 V/m, B) B = 125 10⁻⁸ T , C) f = 9.50 101⁴ Hz, D) λ = 3.158 10⁻⁷ m, E) T = 1.05 10⁻¹⁵ s , F) invisible for humans G) v = c = 3 10⁸ m/s

Explanation:

The expression given for the electric field is

E = 375 cos (1.99 107x + 5.97 105t)

The general formula for the electric field of a transverse traveler is

E = Eo cos (kx-wt)

Where k is the wave number and w the angular velocity

A) The amplitudes as electric is

Emax = Eo = 375 V / m

B) the electric and magnetic field are related

E / B = c

B = E / c

B = 375/3 108

B = 125 10⁻⁸ T

C) angular velocity and frequency is related

.w = 2π f

f = w / 2π

f = 5.97 10¹⁵ / 2π

f = 9.50 101⁴ Hz

D) the speed of light has the formula

c = λ f

λ = c / f

λ = 3 10⁸ / 9.50 10¹⁴

λ = 3.158 10⁻⁷ m

E) The period

T = 1 / f

T = 1 / 9.5 10¹⁴

T = 1.05 10⁻¹⁵ s

F) let's reduce the wavelength nm

λ = 3.158 10⁻⁷ m (10⁹nm / 1m)

λ = 3.158 10²nm = 315.3 nm

The visible radiation range is between 400nm and 700nm. This radiation is ultraviolet and is invisible humans

G) All electromagnetic radiation has a speed at the speed of light (c)

v = c = 3 10⁸ m/s

5 0

3 years ago

Five difference between elastic collision and inelastic collision?​

Five difference between elastic collision and inelastic collision?