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Pachacha [2.7K]
4 years ago
12

PLS HELP

Physics
2 answers:
Bingel [31]4 years ago
4 0
What grade are u in cause like im not really sure
tatyana61 [14]4 years ago
3 0

Answer:

Yellow is the correct answer i believe

Explanation:

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How do you get: a = -ω^2*x from: a = -Aω^2*sen(ωt) ?
Firdavs [7]

Answer:

x = Asin(\omega t)\\v = \frac{dx}{dt} = \omega Acos(\omega t)\\a = \frac{dv}{dt} = -\omega^2Asin(\omega t)= -\omega^2x

8 0
4 years ago
.
Sergio039 [100]

Answer:

The correct answer is B

6 0
3 years ago
A tiger leaps horizontally out of a tree that is 3.70 m high. If she lands 4.80 m from the base of the tree, calculate her initi
Levart [38]

Answer:

Explanation:

Given that

Height of the tree is 3.7m

Therefore yo=3.7m

yox= 0m

The tiger lands 4.8m from the tree

Then, Range x=4.8m

Since she flies horizontally and she lands away from the bottom of the tree, her path will be trajectory as shown in the attachment

Let know the time of flight, using the equation of motion

voy is the initial velocity of the vertical motion of the is the tiger, which is zero at the beginning.

y = y0 + voy*t + ½*g*t²

Given that,

y=3.7m

yo=0m

voy=0m/s

g=9.81m/s²

y = y0 + voy*t + ½*g*t²

3.7=0+0•t+½×9.81×t²

3.7=0+0+4.905t²

3.7=4.905t²

t²=3.7/4.905

t²=0.7543

t=√0.7543

t=0.87sec

Time to reach the ground is

Now to know the initial velocity of the horizontal motion, using equation of motion

x=xo+Voxt

Vox is the horizontal initial velocity of the tiger.

x=xo+Voxt

4.8=0+Vox×0.87

4.8=0+0.87Vox.

4.8=0.87Vox.

Then, Vox=4.8/0.87

Vox=5.52m/s

Then, her initial velocity Vo

Vo=√voy²+vox²

Vo=√0²+5.52²

Vo=√5.52²

Vo=5.52m/s

The initial velocity is 5.52m/s

5 0
4 years ago
What is meant by constructive and destructive interference
LenaWriter [7]
In waveform physics, constructive and destructive interference describes the way two different waves interact with one another. If two waves are aligned such that the peaks of both are in the same spot, the waves experience constructive interference - the two add together and become a single, more powerful wave. The opposite happens if the peak of one meets the trough of the other - the two cancel each other out, and the magnitude of the combined wave is lesser than the individual waves. There are also other, more complex versions of interference if they don’t align cleanly, but the most common descriptions of interference are the ones described above.

Hope this helps!
6 0
4 years ago
To learn the definition of the center of mass for systems of particles and be able to locate it. Imagine throwing a rock upward
ivolga24 [154]

Answer:

a) The center of mass of the system composed of particles of masses m₁ and m₂, is located at a distance longer than 5 m and less than 10 m.

Explanation:

For a group of point masses, located along a straight line, we know, first of all, that the center of mass must be located on this line, as the y-coordinate of the  center of mass is 0, due to no mass has a y-coordinate ≠ 0.

If we know that m₁ < m₂, we can choose to put m₁ just in the origin, so his x-coordinate, is 0 also.

With these premises, we can find mathematically the center of mass as follows:

Xcm = x₂*m₂ / (m₁+m₂)

So, as m₂/m₁+m₂ < 1, the x-coordinate of the center of mass must be located to the left of m₂.

An obvious question arises : How much to the left?

If (in the limit) m₁ =m₂, the factor m₂/ m₁+m₂ would be exactly 1/2.

⇒ Xcm = 1/2 * X₂ = 0.5* 10 m = 5 m

If m₁ < m₂, the center of mass will be more to the right (closer to m₂) than in the limit case when m₁=m₂, so it will be located at a distance longer than 5 m, and less than 10 m (which would be the case for m₁=0).

8 0
3 years ago
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