Average speed= total distance/total time =12km/h
I think this is the solution:
1: U-1, F,-4
2: Na-6, Mo-1, O-4
3: Bi-1, O-1, C-1, I-1
4: In-9, N-1
5: N-2, H-4, S-1, C-1
6: Ge- 15, N-4
7: N-1, H-4, C-1, I-1, O-3
8: H-7, F-1
9: N-1, O-5, H-1, S-1
10: H-8
11: Nb-1, O-1, C-1, I-3
12: C-3, F-3, S-1, O-3, H-1
13: Ag-1, C-1, N-1, O-1
14: Pb-6, H-1, As-1, O-4
Answer:
ωf = 0.16 rad/s
Explanation:
Moment of inertia of the child = mr² = 20(1.6²) = 51.2 kg•m²
Moment of Inertia of the MGR = ½mr² = ½(180)1.6² = 230.4 kg•m²
(ASSUMING it is a uniform disk)
Initial angular momentum of the child = Iω = I(v/r) = 51.2(1.4/1.6) = 44.8 kg•m²/s
Conservation of angular momentum
44.8 = (51.2 + 230.4)ωf
ωf = 0.15909090...
Answer:
The banking angle is 23.84 degrees.
Explanation:
Given that,
Radius of the curve, r = 194 m
Speed of the car, v = 29 m/s
On the banked curve, the centripetal force is balanced by the force of friction such that,




So, the banking angle is 23.84 degrees. Hence, this is the required solution.
Answer:
Explanation:
Given that, the pilot can withstand 9g acceleration which is approximately 88m/s².
Now, the pilot is traveling in a circle of radius
r = 3340 m
And the speed is
v = 495 m/s
Then, acceleration?
The acceleration of a circular motion can be determine using centripetal acceleration
a = v² / r
a = 495² / 3340
a = 73.36 m/s².
Since the acceleration is less that the acceleration the pilot can withstand, then, I think the pilot makes the turn without blacking out and successfully