1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
disa [49]
3 years ago
6

A ball of mass 5 kg attached to a string is swung in a horizontal circle of radius 0.5 m. If the tension in the string is 10 N,

the work done by the tension in one revolution is _____________ J.
Physics
1 answer:
kirill115 [55]3 years ago
8 0

Answer:

0 J

Explanation:

given,

mass of the ball = 5 kg

radius of the horizontal circle = 0.5 m

tension in the string = 10 N

Work done = ?

Work done by the tension in the circular path will be equal to zero.

This is because body moves in circular path, the centripetal force act along the radius of the circle and motion is right angle to the tension on the string.

so, work done = F s cos θ

     θ = 90°,

work done = F s cos 90°        ∵ cos 90° = 0

Work done = 0 J

You might be interested in
A metal wire has a resistance of 13.00 at a temperature of 25.0 degree celsius
Nady [450]

Explanation:

what exactly are you asking for?

4 0
2 years ago
Neutron stars are extremely dense objects that are formed from the remnants of supernova explosions. Many rotate very rapidly. S
Vlada [557]

Answer:

The required angular speed the neutron star is 10992.32 rad/s

Explanation:

Given the data in the question;

mass of the sun M_S = 1.99 × 10³⁰ kg

Mass of the neutron star

M_N = 2( M_S )

M_N = 2( 1.99 × 10³⁰ kg )

M_N = ( 3.98 × 10³⁰ kg )

Radius of neutron star R_N = 13.0 km = 13 × 10³ m

Now, let mass of a small object on the neutron star be m

angular speed be ω_N.

During rotational motion, the gravitational force on the object supplies the necessary centripetal force.

GmM_N = / R_N² = mR_Nω_N²

ω_N² = GM_N = / R_N³

ω_N = √(GM_N = / R_N³)

we know that gravitational G = 6.67 × 10⁻¹¹ Nm²/kg²

we substitute

ω_N = √( (  6.67 × 10⁻¹¹ )( 3.98 × 10³⁰ ) ) / (13 × 10³ )³)

ω_N = √( 2.65466 × 10²⁰ / 2.197 × 10¹²

ω_N = √ 120831133.3636777

ω_N = 10992.32 rad/s

Therefore, The required angular speed the neutron star is 10992.32 rad/s

5 0
3 years ago
How much does the gravitational force of attraction change between two asteroids if the two asteroids drift three times closer t
Katen [24]

Answer:

Increase 9 times

Explanation:

We have Newton formula for attraction force between 2 objects with mass and a distance between them:

F_G = G\frac{M_1M_2}{R^2}

where G =6.67408 \times 10^{-11} m^3/kgs^2 is the gravitational constant. M_1, M_2 is the masses of the 2 objects. and R is the distance between them.

Since the force is inversely proportional to the distance squared, if it is reduced by 3 times, the gravitational force between them would increase by 3^2 = 9 times

6 0
3 years ago
A top-fuel dragster accelerates from rest to a velocity of 100 m/s in 8 s. What is the acceleration?
seropon [69]

Answer:

100 m/s ÷ 8 = 12.5 m/s

Explanation:

You must put multiply (÷)

4 0
3 years ago
If the electron has half the speed needed to reach the negative plate, it will turn around and go towards the positive plate. Wh
In-s [12.5K]

Answer:

 v = -v₀ / 2

Explanation:

For this exercise let's use kinematics relations.

Let's use the initial conditions to find the acceleration of the electron

            v² = v₀² - 2a y

when the initial velocity is vo it reaches just the negative plate so v = 0

           a = v₀² / 2y

now they tell us that the initial velocity is half

          v’² = v₀’² - 2 a y’

          v₀ ’= v₀ / 2

at the point where turn v = 0              

          0 = v₀² /4  - 2 a y '

          v₀² /4 = 2 (v₀² / 2y)  y’

          y = 4 y'

          y ’= y / 4

We can see that when the velocity is half, advance only ¼ of the distance between the plates, now let's calculate the velocity if it leaves this position with zero velocity.

         v² = v₀² -2a y’

         v² = 0 - 2 (v₀² / 2y) y / 4

         v² = -v₀² / 4

         v = -v₀ / 2

We can see that as the system has no friction, the arrival speed is the same as the exit speed, but with the opposite direction.

7 0
3 years ago
Other questions:
  • Manufacturers sometimes use science to make foods more nutritious. Food manufacturers can make reduced fat potato chips, besides
    12·2 answers
  • calculate the force between two objects that have masses of 20 kg and 100 kg separated by a distance of 2.6 m
    15·1 answer
  • What are two things you do ahead of time to prepare for a lab
    7·2 answers
  • Which kinds of objects emit light? A. objects that shine B. hot objects C. distant objects D. colored objects E. all objects
    15·2 answers
  • For any degenerate triplet of states in a 3D infinite potential well, what is the maximum number of electrons allowed?
    15·1 answer
  • The length of a wooden rod is 25.5 cm. What is this length in:<br>(a) millimetres?<br>(b) metres?​
    5·2 answers
  • What are the three types of muscle fibers?
    7·2 answers
  • Which of the following equations illustrates the law of conservation of<br> matter?
    15·1 answer
  • If it is known that a motor battery has an input voltage of 12V and a capacity of 6 Ah, how much power and resistor value is req
    7·1 answer
  • 3. What is the acceleration of a car at rest that stays at rest over 10 seconds?
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!