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I am Lyosha [343]
1 year ago
8

Spiderman is standing on a building and notices some shady characters up to no good on the street below. Rather than leap or

Physics
1 answer:
marissa [1.9K]1 year ago
6 0

The height of the building using second equation of motion is 35.721 m

What is the second equation of motion?

In kinematics, equations of motion are referred to as the fundamental principles of an object's motion, including velocity, location, and acceleration that occur at variable time intervals. These three motion equations control motion in all three dimensions of an item.

Second equation of motion: s = ut +  a(t^2)/2

where,

s = displacement

u = initial velocity

v = final velocity

a = acceleration

t = time of motion

Given, a = 9.8 m/s/s

           t = 2.7 s

Using this equation we find the height of the building,

s = ut +  a(t^2)/2

  = 0 + 9.8 x 2.7 x 2.7/2

  = 71.442/2

  = 35.721 m

Hence, the height of the building is 35.721 m

To learn more about equations of motions from the given link

brainly.com/question/25951773

#SPJ1

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Romashka-Z-Leto [24]

costa rica does not have deserts hoped this helped and have a great day:)


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Charge is uniformly distributed around a ring of radius R and the resulting electric field magnitude E is measured along the rin
Arte-miy333 [17]

Answer:

x=\dfrac{r}{\sqrt2}

Explanation:

Given that

Radius =r

Electric filed =E

Q=Charge on the ring

The electric filed at distance x given as

E=K\dfrac{Q}{(r^2+x^2)^{3/2}}

For maximum condition

\dfrac{dE}{dx}=0

E=K{Q}{(r^2+x^2)^{-3/2}}

\dfrac{dE}{dx}=K{Q}{(r^2+x^2)^{-3/2}}-\dfrac{3}{2}\times 2\times x\times K{Q}{(r^2+x^2)^{-5/2}}

For maximum condition

\dfrac{dE}{dx}=0

K{Q}{(r^2+x^2)^{-3/2}}-\dfrac{3}{2}\times 2\times x\times K{Q}{(r^2+x^2)^{-5/2}}=0

r^2+x^2-3x^2=0

x=\dfrac{r}{\sqrt2}

At x=\dfrac{r}{\sqrt2} the electric field will be maximum.

3 0
2 years ago
Suppose that you are swimming in a river while a friend watches from the shore. In calm water, you swim at a speed of 1.25 m/s .
aliya0001 [1]

Answer: The observing friend will the swimmer moving at a speed of 0.25 m/s.

Explanation:

  • Let <em>S</em> be the speed of the swimmer, given as 1.25 m/s
  • Let S_{0} be the speed of the river's current given as 1.00 m/s.

  • Note that this speed is the magnitude of the velocity which is a vector quantity.
  • The direction of the swimmer is upstream.

Hence the resultant velocity is given as, S_{R} = S — S 0S_{0}

S_{R} = 1.25 — 1

S_{R} = 0.25 m/s.

Therefore, the observing friend will see the swimmer moving at a speed of 0.25 m/s due to resistance produced by the current of the river.

6 0
3 years ago
I need help with these questions
Feliz [49]
7. PE=0.5×700n/m×0.9m^2
0.9^2=0.81m
0.5×700×0.81= 283.5J

8. 2000=0.5×(x)×1.5m^2
1.5^2= 0.25
0.25×0.5=0.125
2000=0.125 (x)
2000/0.125=x
x=16000 n/m

9. 4000=0.5 (375 n/m)×(x)^2
0.5×187.5 (x)
4000/187.5=21.3333333333


6 0
3 years ago
Critical angle of glass is 42 .what does it mean?​
elena55 [62]

Answer:

i think..its fraction that its have multiple fractions on it..if you minus the 397 000-355 it should be 381+ so i say if you get the 5 multiply it by 9!! so you will get it!

Explanation:

HOPE IT HELPS!!

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