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1 year ago

Spiderman is standing on a building and notices some shady characters up to no good on the street below. Rather than leap or

Physics

1 answer:

marissa [1.9K]1 year ago

6 0

The height of the building using second equation of motion is 35.721 m

What is the second equation of motion?

In kinematics, equations of motion are referred to as the fundamental principles of an object's motion, including velocity, location, and acceleration that occur at variable time intervals. These three motion equations control motion in all three dimensions of an item.

Second equation of motion: s = ut + a(t^2)/2

where,

s = displacement

u = initial velocity

v = final velocity

a = acceleration

t = time of motion

Given, a = 9.8 m/s/s

t = 2.7 s

Using this equation we find the height of the building,

s = ut + a(t^2)/2

= 0 + 9.8 x 2.7 x 2.7/2

= 71.442/2

= 35.721 m

Hence, the height of the building is 35.721 m

To learn more about equations of motions from the given link

brainly.com/question/25951773

#SPJ1

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3 years ago

Read 2 more answers

A square plate of edge length 9.0 cm and negligible thickness has a total charge of 6.90 10-6 C. Estimate the magnitude E of the

SVETLANKA909090 [29]

Answer:

E= 4.35*10^6 N/C

Explanation:

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α= 6.9*10^-6/9*10^-2 = 7.7*10^-5C/m2

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2 years ago

What nonliving materials are important to living things?

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3 years ago

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A man starts walking north at 3 ft/s from a point P. Five minutes later a woman starts walking south at 4 ft/s from a point 500

mrs_skeptik [129]

Answer:

ds/dt = 6.98 ft/s

Explanation:

Given:

- The speed of man due north Vm = 3 ft/s

- The speed of woman due south Vw = 4 ft/s

- Woman starts walking 5 mins later than man

Find:

At what rate are the people moving apart 15 min after the woman starts walking?

Solution:

- The total time for which the man is walking due north from P, is Tm:

Tm = 5 + 15 = 20 mins

- The total distance traveled by man in Tm mins is:

Dm = Tm*Vm

Dm = 20*60*3

Dm = 3,600 ft

- The total time for which the woman is walking due south from 500 ft due east from P, is Tw:

Tw = 15 = 15 mins

- The total distance traveled by man in Tw mins is:

Dw = Tw*Vw

Dw = 15*60*4

Dw = 3,600 ft

- The displacement between man and woman at any instance is (s) which can be related by pythagoras theorem as follows:

s^2 = (dm + dw)^2 + 500^2

Where, dm : Distance travelled by man at any time Tm

dw : Distance travelled by woman at any time Tw

- Differentiate s with respect to t:

2s*ds/dt = 2*(dm + dw)*(Vm + Vw)

s*ds/dt = (dm + dw)*(Vm + Vw)

ds/dt = [ (dm + dw)*(Vm + Vw) ] / s

- Evaluate the rate of separation of man and woman ds/dt by evaluating at instance Tm = 20 mins and Tw = 15 mins. We have:

ds/dt = [ (Dm + Dw)*(Vm + Vw) ] / sqrt ( (Dm + Dw)^2 + 500^2 )

- Plug in the values:

ds/dt = [ (3600 + 3600)*(3 + 4) ] / [sqrt ( (3600 + 3600)^2 + 500^2 )]

ds/dt = 6.98 ft/s

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3 years ago