The height of the building using second equation of motion is 35.721 m
What is the second equation of motion?
In kinematics, equations of motion are referred to as the fundamental principles of an object's motion, including velocity, location, and acceleration that occur at variable time intervals. These three motion equations control motion in all three dimensions of an item.
Second equation of motion: s = ut + a(t^2)/2
where,
s = displacement
u = initial velocity
v = final velocity
a = acceleration
t = time of motion
Given, a = 9.8 m/s/s
t = 2.7 s
Using this equation we find the height of the building,
s = ut + a(t^2)/2
= 0 + 9.8 x 2.7 x 2.7/2
= 71.442/2
= 35.721 m
Hence, the height of the building is 35.721 m
To learn more about equations of motions from the given link
brainly.com/question/25951773
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