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alisha [4.7K]
1 year ago
10

Given f(x)=3x+5 describe how the graph of g compares with the graph of f. g(x)=3(0.1)+5

Mathematics
1 answer:
mrs_skeptik [129]1 year ago
6 0

The given function f(x) is:

f(x)=3x+5

And the other given function g(x) is:

g(x)=3(0.1x)+5

g(x) in comparison with f(x) has the next transformation:

1. g(x)=f(bx): g(x)=3(0.1x)+5. This is a horizontal stretch: the x-coordinates will change as:

(x,y)\rightarrow(\frac{x}{0.1},y)

This is the graph of both functions:

The red-one is f(x) and the blue-one is g(x).

Then for example when the coordinates of f(x) are (1,8) for g(x) the coordinates will be:

(\frac{1}{0.01},8)=(10,8)

Then, the slope of f(x) has a greater value than the slope of g(x), since the change on the x-axis is bigger in the g(x) graph for the.

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Jacob is a teacher. He made 75 cookies to give to his students on the first day of school. He gave 2 cookies to each student who
Lisa [10]

Answer:

See explanation

Step-by-step explanation:

Jacob has 75 cookies.

He gave 2 cookies to each student.

Complete the table:

\begin{array}{cc}\text{Number of student arrived}&\text{Number of cookies left}\\1&75-2=73\\2&73-2=71\\3&71-2=69\\...&...\end{array}

Let n be the number of students. After nth student arrived Jacob had left

g(n)=75-2n

cookies.

This is an arithmetic sequence with

g_1=g(1)=73\\ \\d=-2

Thus,

g_{n}=g_{n-1}-2\\ \\g(n)=g(n-1)-2

3 0
3 years ago
Read 2 more answers
What is the area of a circle with a diameter of 21 centimeters?
sattari [20]
Area of a circle: πr²

Data:
diameter:  21 cm
radius=diameter/2=21 cm/2=10.5 cm

area of this circle: π(10.5 cm)²=110.25π cm²  (≈346.36 cm²)

Answer: area=110.25π cm²
4 0
3 years ago
Read 2 more answers
HELP URGENT PLEASE!!!!!!!!!!!!!!
leonid [27]

Answer:

The supplement of 89° is the angle that when added to 89° forms a straight angle (180° ).

Step-by-step explanation:

4 0
3 years ago
The distribution of SAT II Math scores is approximately normal with mean 660 and standard deviation 90. The probability that 100
gayaneshka [121]

Using the <em>normal distribution and the central limit theorem</em>, it is found that there is a 0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

  • It measures how many standard deviations the measure is from the mean.
  • After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
  • By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation s = \frac{\sigma}{\sqrt{n}}.

In this problem:

  • The mean is of 660, hence \mu = 660.
  • The standard deviation is of 90, hence \sigma = 90.
  • A sample of 100 is taken, hence n = 100, s = \frac{90}{\sqrt{100}} = 9.

The probability that 100 randomly selected students will have a mean SAT II Math score greater than 670 is <u>1 subtracted by the p-value of Z when X = 670</u>, hence:

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{670 - 660}{9}

Z = 1.11

Z = 1.11 has a p-value of 0.8665.

1 - 0.8665 = 0.1335.

0.1335 = 13.35% probability that 100 randomly selected students will have a mean SAT II Math score greater than 670.

To learn more about the <em>normal distribution and the central limit theorem</em>, you can take a look at brainly.com/question/24663213

7 0
2 years ago
Sin o = - 2/2<br> Select all angle measures for which
finlep [7]
120^ is the answer for this problem
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