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alisha [4.7K]
1 year ago
10

Given f(x)=3x+5 describe how the graph of g compares with the graph of f. g(x)=3(0.1)+5

Mathematics
1 answer:
mrs_skeptik [129]1 year ago
6 0

The given function f(x) is:

f(x)=3x+5

And the other given function g(x) is:

g(x)=3(0.1x)+5

g(x) in comparison with f(x) has the next transformation:

1. g(x)=f(bx): g(x)=3(0.1x)+5. This is a horizontal stretch: the x-coordinates will change as:

(x,y)\rightarrow(\frac{x}{0.1},y)

This is the graph of both functions:

The red-one is f(x) and the blue-one is g(x).

Then for example when the coordinates of f(x) are (1,8) for g(x) the coordinates will be:

(\frac{1}{0.01},8)=(10,8)

Then, the slope of f(x) has a greater value than the slope of g(x), since the change on the x-axis is bigger in the g(x) graph for the.

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Answer:

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Step-by-step explanation:

Kindly note the 2nd equation in the above question formed will be :

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2 years ago
I’ve tried to work this out but I can’t get it figured out. Can someone help me
Bas_tet [7]
G(2) = -4(2) = -8
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3 years ago
Which equation represents the graphed function?
nadezda [96]

9514 1404 393

Answer:

  y = 1/4x -2

Step-by-step explanation:

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  m = rise/run = 1/4

The y-intercept (b) is where the line crosses the y-axis, at y = -2.

The equation in slope-intercept form is ...

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3 years ago
- 5<br> 4<br> =<br> 2x - 3<br> 5x -5
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Answer:

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3 0
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Please help: linear algebra problem. (Linear combinations)
DochEvi [55]

Answer:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

This tells us that:

A=\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right]

b=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

Step-by-step explanation:

So we are saying we have scalars, c and d, such that:

c\left[\begin{array}{ccc}5\\5\\ 3\end{array}\right]+d\left[\begin{array}{ccc}7\\-8\\-9\end{array}\right]=\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right].

So we want to find a way to express this as:

Ax=b where x is the scalar vector, \left[\begin{array}{ccc}c\\d\end{array}\right].

So we can write this as:

\left[\begin{array}{ccc}5&7\\5&-8\\3&-9\end{array}\right] \left[\begin{array}{ccc}c\\d\end{array}\right] =\left[\begin{array}{ccc}-16\\3\\-15\end{array}\right]

3 0
3 years ago
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