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DaniilM [7]
3 years ago
6

Bodies A and B have equal mass. Body B is initially at rest. Body A collides with body B in a one-dimensional elastic collision.

Which statement is true?
A. BODY A COMES TO REST BODY B STARTS MOVING WITH INITIAL VELOCITY OF BODY A

B. THE MOMENTUM OF THE SYSTEM IS NOT CONSERVED

C.THE KINETIC ENERGY OF THE SYSTEM IS NOT CONSERVED

D.THE FINAL VELOCITY
Physics
2 answers:
inn [45]3 years ago
6 0
After looking on the scaleattached with the question I recognized the right answer in the first option represented above. A. BODY A COMES TO REST BODY B STARTS MOVING WITH INITIAL VELOCITY OF BODY A - is definitely the only correct answer which perfectly concides with the given task.Hope you still need the answer it because this one I gave you is really useful.
jek_recluse [69]3 years ago
4 0
According to the statement " Collision <span>between two bodies in which the total kinetic energy of the two bodies after the collision is equal to their total kinetic energy before the collision."
The best answer is :
Option A " </span><span>BODY A COMES TO REST BODY B STARTS MOVING WITH INITIAL VELOCITY OF BODY A "</span>
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How dose an atom change if all of its electrons are removed
cluponka [151]

Answer:

The atom becomes a positively charged ion.

Explanation:

  1. The building blocks of an atom are protons, neutrons, and electrons.
  2. The protons and neutrons present in the core of the atom are called nucleus.
  3. The electrons are scattered in an ordered way around the nucleus.
  4. The protons are positively charged and the electrons are negatively charged particles. The neutrons do not possess any charges.
  5. Binding energy is supplied to the atom to remove an electron.
  6. It is possible to remove the electrons of the lighter elements.
  7. When an electron is removed from the hydrogen atom. It becomes positively charged ion or simply proton.
  8. When all of the electrons are removed from the helium atom, it becomes a positively charged α particle.
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7 0
3 years ago
What scientific observation did Edwin Hubble use to determine distances between galaxies?
Cerrena [4.2K]

Answer: the expanding universe

Explanation:

Hope that helps!

7 0
3 years ago
A small child has a wagon with a mass of 10 kilograms. The child pulls on the wagon with a force of
Sholpan [36]
F=ma
where:
F - force
m - mass
a - acceleration 

We transform this formula to get a:
a= \frac{F}{m}
a=\frac{2}{10}\frac{N}{kg}=0.2\frac{m}{s^{2}}
4 0
3 years ago
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In a swimming meet, the swimmers swim a total of 8 laps of a 50-meter-long swimming pool. What is the distance traveled by a swi
N76 [4]

Answer:

The swimmer has a distance traveled of 800 meters.

The final displacement of the swimmer is 0 meters.

Explanation:

A lap is a round trip made by a swimmer in the pool, so that the distance traveled by swimmer is sixteen times the length of the swimming pool. That is:

s = \left(2\,\frac{travels}{lap} \right)\cdot \left(8\,laps \right)\cdot \left(50\,\frac{m}{travel}\right)

s = 800\,m

A swimmer has a distance traveled of 800 meters.

The displacement is the distance between swimmer and a reference point, let suppose that reference point is located at the beginning of the first lap. Hence, the final displacement of the swimmer is 0 meters.

7 0
3 years ago
The SAME amount of current I passes through three different resistors. R2 has twice the cross-sectional area and the same length
Snezhnost [94]

Answer:

resistor R₂ has the lowest current density

Explanation:

The current density is

          j = I / A

now let's analyze each case

a) R₂ has an area 2A₀ and a length L₀ that R₁

b) R₃ has an area Ao and a length 3L₀ what R₁

we can see that all the area is given in relation to the resistance R₁

 

the current density in R₁ is

         j₁ = I / A₀

the current density in R₂

         j₂ = I / 2A₀

         j₂ 2 = ½ I/A₀

the current density in R₃

         j₃ = I / A₀

         j₂ < j₁ = j₃

therefore resistor R₂ has the lowest current density

5 0
3 years ago
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