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Zina [86]
3 years ago
7

What does this equation mean FeDe=FrDr

Physics
1 answer:
rjkz [21]3 years ago
3 0
Not exactly the best way to describe it but, it is used to calculate resistance of a lever as in the use of a pry bar or pulley. Technology used to increase output with little input.
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When an atom that has no charge loses two electrons, it becomes a
kicyunya [14]

Answer:

positive ion

Explanation:

due to the fact it loses electrons there is 2 more protons than electrons

3 0
3 years ago
Using the definition of moment of inertia, calculate icm, the moment of inertia about the center of mass, for this object.
Step2247 [10]
<span> The masses have no inertia about their own CM, and "the object" is the two masses. </span>
<span>1. Icm (at point A) = 2mr^2 
hope this helps</span>
3 0
3 years ago
Consider the data collected in science class. Different masses were thrown with varied amounts of
lesya [120]

Answer:

A: In all cases, the acceleration was the same.

Explanation:

I know this because its a clear obvious answer not only that it was one of my USA TESTPREP questions and it was right.

All you mainly have to do is the math - F=ma , In each case , the acceleration is 5 m/s squared

4 0
3 years ago
Read 2 more answers
the diagram deliver of uniform mass supported at the middle point six Queens of equal mass are placed at mark 4 on on the lift h
gtnhenbr [62]

Answer:

hmm I don’t understand

Explanation:

5 0
3 years ago
How long does it take an automobile traveling 66.7 km/h to become even with a car that is traveling in another lane at 52.7 km/h
tresset_1 [31]

Answer:

The  time taken is  t =  32.5 \  s

Explanation:

From the question we are told that

   The  speed  of  first car is  v_1  =  66.7 \ km/h  =  18.3 \  m/s

    The  speed  of  second car is v_2  =  52.7 \ km/h  =  14.64 \  m/s

   The  initial distance of separation is  d =  119 \ m

The distance covered by first car is mathematically represented as

     d_t =  d_i  +  d_f

Here  d_i is the initial distance which is  0 m/s

  and  d_f  is the final distance covered which is  evaluated as d_f  =  v_1 * t

So

     d_t =  0 \  m/s  +  (v_1 * t )

     d_t =  0 \  m/s  +  (18.3 * t )

The distance covered by second  car is mathematically represented as

     d_t =  d_i  +  d_f

Here  d_i is the initial distance which is  119 m

  and  d_f  is the final distance covered which is  evaluated as d_f  =  v_2* t

       d_t =  119  + 14.64 *  t

Given that the two car are now in the same position we have that

    119  + 14.64 *  t  =   0   +  (18.3 * t )

   t =  32.5 \  s

6 0
3 years ago
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