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Bezzdna [24]
3 years ago
8

If the net force acting on a laboratory cart as is it being pushed down the hallway is zero, then what is the relationship betwe

en Fa and Ff?
Physics
1 answer:
Zarrin [17]3 years ago
7 0

Answer:

Fa = -Ff provided that the angle between Fa and Ff is zero

Explanation:

Since the net force is zero, the sum of adding all external forces onto the cart must be zero.

Assuming there is no other forces acting on the cart and Fa acting in the same plane as Fc (i.e. zero angle between acting forces),

Fa + Ff = 0

Hence

Fa = -Ff

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4 years ago
Hydrogen atoms are placed in an external magnetic field. The protons can make transitions between states in which the nuclear sp
gregori [183]

Answer:

Magnetic field = 0.534 T

Explanation:

The solving is on the attach document.

6 0
3 years ago
In rural areas, water is often extracted from underground by pumps. Consider an underground water source whose free surface is 6
stealth61 [152]

Answer:

W = 9533.09 Watt

Explanation:

given,

diameter of pipe inlet, d₁ = 10 cm

                                      r₁ = 5 cm

diameter of pipe outlet, d₂ = 15 cm

                                      r₂= 7.5 cm

head upto water level is to rise = 60 + 5

                                          = 65 m

flow rate = 0.015 m³/s

we know

A₁ v₁ = A₂ v₂ = Q  

 π r₁² v₁ = π r₂² v₂  = 0.015

 v_1= \dfrac{r_2^2}{r_1^2} v_2

 v_1= \dfrac{7.5^2}{5^2} v_2

 v_1= 2.25 v_2

 v_2 = \dfrac{0.015}{\pi r_2^2}

 v_2 = \dfrac{0.015}{\pi 0.075^2}

    v₂ = 0.848 m/s

    v₁ = 1.908 m/s

Applying Bernoulli's equation

 P_p = \dfrac{1}{2}\rho (v_2^2-v_1^2)+ \rho g h

 P_p= \dfrac{1}{2}\times 1000\times (0.848^2-1.908^2)+ 1000\times 9.8\times 65

 P_p= 635539.32 Pa

 P_p is the pump pressure

Power of the pump

W = P_p x Q

W = 635539.32 x 0.015

W = 9533.09 Watt

6 0
4 years ago
The position of a particle moving on x-axis is given by x(t)=t^2 + 2, it’s average velocity in the final interval from t=1 to t=
san4es73 [151]

Answer:

The average velocity is 2 m/s.

Explanation:

The velocity of the particle is the time derivative of its position x(t):

$v =\frac{dx(t)}{dt} = \frac{d}{dt}[t^2+2] $

$v =2t $

Now the average from t=1 and t=2 is

v_{avg} = \dfrac{v(2)-v(1)}{2-1} = \dfrac{2(2)-2(1)}{1}

\boxed{v_{avg} = 2 m/s} \text{    ( If the units are m/s)}

Thus, the average velocity is 2 m/s.

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Explicitly solve the Heisenberg equations of motion to find the time–dependent raising and lowering (creation and annihilation)
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see detailed solution attached.

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