Weight of the carriage 
Normal force 
Frictional force 
Acceleration 
Explanation:
We have to look into the FBD of the carriage.
Horizontal forces and Vertical forces separately.
To calculate Weight we know that both the mass of the baby and the carriage will be added.
- So Weight(W)
To calculate normal force we have to look upon the vertical component of forces, as Normal force is acting vertically.We have weight which is a downward force along with 
, force of 
acting vertically downward.Both are downward and Normal is upward so Normal force 
- Normal force (N)
- Frictional force (f)
To calculate acceleration we will use Newtons second law.
That is Force is product of mass and acceleration.
We can see in the diagram that 
and 
component of forces.
So Fnet = Fy(Horizontal) - f(friction) 
- Acceleration (a) =
So we have the weight of the carriage, normal force,frictional force and acceleration.
Answer:
Explanation:
I think this answer would be 1m to the left.
let the distance of pillar is "r" from one end of the slab
So here net torque must be balance with respect to pillar to be in balanced state
So here we will have
here we know that
mg = 19600 N
Mg = 400,000 N
L = 20 m
from above equation we have
so pillar is at distance 10.098 m from one end of the slab
Answer:
A line of symmetry is a line that separates a shape into two identical halves.
Rotational symmetry is the same thing except when you rotate the object, it has to have the exact same line of symmetry.
<u><em>Hope this helps!!!</em></u>
Answer:
Acceleration = 9 × 10^5 m/s^2 ( deceleration )
Explanation:
From the first equation of motion:
V = u + at
15000 = 30000 + 60a
a = ( 15000-30000)/60
a = 9 × 10^5 m/s^2
