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chubhunter [2.5K]
3 years ago
12

Two waves travel at the same speed, but one has a larger period. What other parameter/s would be affected by this? (Check all th

at apply)
The larger period would leave to a smaller wavelength.

The larger period would lead to a smaller frequency.

The smaller period would lead to a larger wavelength.

The larger period would lead to a larger frequency.


explain please (two answers)
Physics
1 answer:
Contact [7]3 years ago
8 0

Answer:

The SMALLER period would lead to a larger wavelength.

The larger period would lead to SMALLER FREQUENCY.

Explanation:

Smaller periods will have larger wavelengths because their periods move more as opposed to a larger period that won't move as much. Think of it like sound waves that go up and down really fast (those have smaller periods) as opposed to ones that take their time in transitioning from sound to sound (longer time to go from note to note so not as much movement).

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Cohort studies allow the investigator to examine multiple outcomes and multiple exposures. Consider the following three exposure
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Answer:

See the explanation for the answer.

Explanation:

                          <u>Cohort study for smoking</u>

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1. People at risk of lung cancer due to smoking

2. Influence of outdoor air pollution in lung cancer

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4. Occupational factors and housing factor were observed.

                       

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2. Observing value in summer.

3. Correlating vitamin D value with weather and age

4. 25-hydroxy vitamin D was observed.

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1. Allergic and asthma risked people were observed.

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3 0
3 years ago
A shell is fired from the ground with an initial speed of 1.60 × 103 m/s (approximately five times the speed of sound) at an ini
Volgvan

Answer:

The horizontal range will be 2.55\times 10^5m

Explanation:

We have given initial speed of the shell u = 1.6\times 10^3m/sec

Angle of projection = 51°

Acceleration due to gravity g=9.8m/sec^2

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Horizontal range in projectile motion is given by

R=\frac{u^2sin2\Theta }{g}=\frac{(1.60\times 10^3)^2sin(2\times 51^{\circ})}{9.81}=2.55\times 10^5m

So the horizontal range will be 2.55\times 10^5m

6 0
3 years ago
Machines can be made more efficient by reducing ___________________.
Aleks04 [339]

Answer:

friction

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3 years ago
Rosa eats a peanut butter sandwich for lunch. Peanut butter contains a lot
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4 0
3 years ago
The power of the kettle was 2.6 kW
faltersainse [42]

Answer:

Cp = 4756 [J/kg*°C]

Explanation:

In order to calculate the specific heat of water, we must use the equation of energy for heat or heat transfer equation.

Q = m*Cp*(T_f - T_i)/t

where:

Q = heat transfer = 2.6 [kW] = 2600[W]

m = mass of the water = 0.8 [kg]

Cp = specific heat of water [J/kg*°C]

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Now clearing the Cp, we have:

Cp = Q*t/(m*(T_f - T_i))

Now replacing

Cp = (2600*120)/(0.8*(100-18))

Cp = 4756 [J/kg*°C]

7 0
3 years ago
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