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chubhunter [2.5K]
2 years ago
12

Two waves travel at the same speed, but one has a larger period. What other parameter/s would be affected by this? (Check all th

at apply)
The larger period would leave to a smaller wavelength.

The larger period would lead to a smaller frequency.

The smaller period would lead to a larger wavelength.

The larger period would lead to a larger frequency.


explain please (two answers)
Physics
1 answer:
Contact [7]2 years ago
8 0

Answer:

The SMALLER period would lead to a larger wavelength.

The larger period would lead to SMALLER FREQUENCY.

Explanation:

Smaller periods will have larger wavelengths because their periods move more as opposed to a larger period that won't move as much. Think of it like sound waves that go up and down really fast (those have smaller periods) as opposed to ones that take their time in transitioning from sound to sound (longer time to go from note to note so not as much movement).

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If you measured all the energy related to motion and all the stored energy in the particles of a substance, which would you be m
Nady [450]

If you measured all the energy related to motion and all the stored energy in the particles of a substance, you would be measuring the thermal energy of the particles. If there is movement of the particles, they are also releasing energy in the form of heat.

3 0
3 years ago
The process of combining two small nuclei into one nucleus of larger mass is called _____.
fiasKO [112]
The process of splitting one large nucleus into
smaller ones is nuclear fission.

The process of combining two small nuclei into
one larger one is nuclear fusion.
3 0
3 years ago
Read 2 more answers
A 3.15-kg object is moving in a plane, with its x and y coordinates given by x = 6t2 − 4 and y = 5t3 + 6, where x and y are in m
ArbitrLikvidat [17]

Answer:

<h2>206.67N</h2>

Explanation:

The sum of force along both components x and y is expressed as;

\sum Fx = ma_x  \ and \ \sum Fy = ma_y

The magnitude of the net force which is also known as the resultant will be expressed as R =\sqrt{(\sum Fx)^2 + (\sum Fx )^2}

To get the resultant, we need to get the sum of the forces along each components. But first lets get the acceleration along the components first.

Given the position of the object along the x-component to be x = 6t² − 4;

a_x = \frac{d^2 x }{dt^2}

a_x = \frac{d}{dt}(\frac{dx}{dt} )\\ \\a_x = \frac{d}{dt}(6t^{2}-4  )\\\\a_x = \frac{d}{dt}(12t  )\\\\a_x = 12m/s^{2}

Similarly,

a_y = \frac{d}{dt}(\frac{dy}{dt} )\\ \\a_y = \frac{d}{dt}(5t^{3} +6 )\\\\a_y = \frac{d}{dt}(15t^{2}   )\\\\a_y = 30t\\a_y \ at \ t= 2.15s; a_y = 30(2.15)\\a_y = 64.5m/s^2

\sum F_x = 3.15 * 12 = 37.8N\\\sum F_y = 3.15 * 64.5 = 203.18N

R = \sqrt{37.8^2+203.18^2}\\ \\R = \sqrt{1428.84+41,282.11}\\ \\R = \sqrt{42.710.95}\\ \\R = 206.67N

Hence, the magnitude of the net force acting on this object at t = 2.15 s is approximately 206.67N

7 0
3 years ago
A man attaches a divider to an outdoor faucet so that water flows through a single pipe of radius 9.25 mm into four pipes, each
irinina [24]

Answer:

1.24 m/s

Explanation:

Metric unit conversion:

9.25 mm = 0.00925 m

5 mm = 0.005 m

The volume rate that flow through the single pipe is

\dot{V} = vA = 1.45 * \pi * 0.00925^2 = 0.00039 m^3/s

This volume rate should be constant and divided into the 4 narrower pipes, each of them would have a volume rate of

\dot{V_n} = \dot{V} / 4 = 0.00039 / 4 = 9.74\times10^{-5} m^3/s

So the flow speed of each of the narrower pipe is:

v_n = \frac{\dot{V_n}}{A_n} = \frac{\dot{V_n}}{\pi r_n^2}

v_n = \frac{9.74\times10^{-5}}{\pi 0.005^2} = 1.24 m/s

8 0
3 years ago
A racing car is travelling at 70 m/s and accelerates at -14 m/s2. What would the car’s speed be after 3 s?
Leno4ka [110]
<h3><u>Question</u><u>:</u></h3>

A racing car is travelling at 70 m/s and accelerates at -14 m/s^2. What would the car’s speed be after 3 s?

<h3><u>Statement:</u></h3>

A racing car is travelling at 70 m/s and accelerates at -14 m/s^2.

<h3><u>Solution</u><u>:</u></h3>
  • Initial velocity (u) = 70 m/s
  • Acceleration (a) = -14 m/s^2
  • Time (t) = 3 s
  • Let the velocity of the car after 3 s be v m/s
  • By using the formula,

v = u + at, we have

v = 70 + ( - 14)(3) \\  =  > v = 70 - 42 \\  =  > v = 28

  • So, the velocity of the car after 3 s is 28 m/s.
<h3><u>Answer:</u></h3>

The car's speed after 3 s is 28 m/s.

Hope it helps

3 0
3 years ago
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