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chubhunter [2.5K]
3 years ago
12

Two waves travel at the same speed, but one has a larger period. What other parameter/s would be affected by this? (Check all th

at apply)
The larger period would leave to a smaller wavelength.

The larger period would lead to a smaller frequency.

The smaller period would lead to a larger wavelength.

The larger period would lead to a larger frequency.


explain please (two answers)
Physics
1 answer:
Contact [7]3 years ago
8 0

Answer:

The SMALLER period would lead to a larger wavelength.

The larger period would lead to SMALLER FREQUENCY.

Explanation:

Smaller periods will have larger wavelengths because their periods move more as opposed to a larger period that won't move as much. Think of it like sound waves that go up and down really fast (those have smaller periods) as opposed to ones that take their time in transitioning from sound to sound (longer time to go from note to note so not as much movement).

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A 6cm diameter horizontal pipe gradually narrows to 4cm.
Rom4ik [11]

Answer:Q=0.5612 m^3/s

Explanation:

Given

diameter of pipe(d_1)=6 cm

diameter of pipe(d_2)=4 cm

P_1=32 kPa

P_2=24 kPa

A_1=\frac{\pi }{4}6^2=9\pi cm^2

A_2=\frac{\pi }{4}4^2=4\pi cm^2

v_1=\frac{Q}{A_1}

Applying bernoulli's equation

\frac{P_1}{\rho g}+\frac{v^2_1}{2g}+z_1=\frac{P_2}{\rho g}+\frac{v^2_2}{2g}+z_2

\frac{P_1}{\rho g}+\frac{\frac{Q^2}{A_1^2}}{2g}+z_1=\frac{P_2}{\rho g}+\frac{\frac{Q^2}{A_2^2}}{2g}+z_2

since z_1=z_2

\frac{32\times 10^3}{10^3\times 9.81}+\frac{Q^2}{2A_1^2g}=\frac{24\times 10^3}{10^3\times 9.81}+\frac{Q^2}{2A_2^2g}

Q^2=\frac{8\times 2\times 81\pi ^2\times 16\pi ^2\times 10^{-4}}{65\pi ^2}

Q^2=3149.3722\times 10^{-4}

Q=\sqrt{3149.3722\times 10^{-4}}

Q=0.5612 m^3/s

4 0
3 years ago
Place these bodies of our solar system in the proper order of formation.
earnstyle [38]
The four inner planets, those closest to the Sun, are Mercury, Venus, Earth, and Mars. They are smaller and composed mainly of metals and rocks. The four outer planets — Jupiter, Saturn, Uranus, and Neptune — are larger and composed mostly of gases.
4 0
4 years ago
Read 2 more answers
2. If it takes Ashley 3 seconds to run from the batter’s box to first base at an average speed of 6.5 meters per second, what is
Semmy [17]
6.5 meters per second mutiplied by 3 seconds and you get 19.5 meters
8 0
3 years ago
Read 2 more answers
A stagehand starts sliding a large piece of stage scenery originally at rest by pulling it horizontally with a force of 176 N. W
Diano4ka-milaya [45]

<u>Answer:</u>

Option (a)

<u>Explanation :</u>

A stage hand starts sliding a large piece of stage scenery originally at rest by pulling it horizontally with a force of 176 N.

Hence Force applied  \text { Fapplied }=176 \mathrm{N}

Force on piece of scenery \mathrm{F}_{\mathrm{g}}=490 \mathrm{N}

\Sigma \mathrm{F} \mathrm{y}=\mathrm{F} \mathrm{n}-\mathrm{Fg}=0

\mathrm{Fn}=\mathrm{Fg}

\mathrm{FS}_{\mathrm{max}}=\mathrm{F}_{\mathrm{applied}}

µk = \frac{\mathrm{Fs} \max }{\mathrm{Fn}}

=  \frac{\text { Fapplied }}{\mathrm{Fg}}

=\frac{176}{490} =0.36

coefficient of static friction is 0.36

6 0
4 years ago
A comet fragment of mass 1.96 × 1013 kg is moving at 6.50 × 104 m/s when it crashes into Callisto, a moon of Jupiter. The mass o
Andrej [43]

Answer:

Recoil speed, 1.17\times 10^{-5}\ m/s                          

Explanation:

Given that,

Mass of the comet fragment, m_1=1.96\times 10^{13}\ kg

Speed of the comet fragment, v_1=6.5\times 10^4\ m/s

Mass of Callisto, m_2=1.08\times 10^{23}\ kg

The collision is completely inelastic. Assuming for this calculation that Callisto's initial momentum is zero. So,

m_1v_1=(m_2+m_2)V

V is recoil speed of Callisto immediately after the collision.

V=\dfrac{m_1v_1}{(m_2+m_2)}\\\\V=\dfrac{1.96\times 10^{13}\times 6.5\times 10^4}{(1.96\times 10^{13}+1.08\times 10^{23})}\\\\V=1.17\times 10^{-5}\ m/s

So, the recoil speed of Callisto immediately after the collision is 1.17\times 10^{-5}\ m/s

6 0
3 years ago
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