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Rudiy27
1 year ago
6

The can of corn shown is a right circular cylinder with a height of 11 cm. The volume of the can is 486 cubic centimeters. What

is the approximate radius of the can of corn in centimeters? Use 3.14 for π.A. 1.3B. 3.8C. 7.0D. 14.1

Mathematics
1 answer:
hammer [34]1 year ago
6 0

SOLUTION

Since the can is a cylinder, we will use the formula for volume of a cylinder to solve the problem.

Volume of a cylinder is given as

\begin{gathered} V=\pi r^2h \\ where\text{ r = radius = ?} \\ h=height=11cm \\ V=volume=486cm^3 \end{gathered}

Applying we have

\begin{gathered} V=\pi r^2h \\ 486=3.14\times r^2\times11 \\ 486=34.54r^2 \\ r^2=\frac{486}{34.54} \\ r=\sqrt{14.07064} \\ r=3.75108 \end{gathered}

Hence the answer is 3.8, the second option is the answer

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a helicopter rises 800 feet and then travels east 1,100 feet. how far is this from its starting point?
sesenic [268]

wouldn't it be 300 ft east??

8 0
3 years ago
Ex 2.8<br> 3. find the maximum value of y for the curve y=x^5 -3 for -2≤x≤1
harkovskaia [24]
y=x^5-3\\ y'=5x^4\\\\ 5x^4=0\\ x=0\\ 0\in [-2,1]\\\\ y''=20x^3\\\\&#10;y''(0)=20\cdot0^3=0

The value of the second derivative for x=0 is neither positive nor negative, so you can't tell whether this point is a minimum or a maximum. You need to check the values of the first derivative around the point.
But the value of 5x^4 is always positive for x\in\mathbb{R}\setminus \{0\}. That means at x=0 there's neither minimum nor maximum.
The maximum must be then at either of the endpoints of the interval [-2,1].
The function y is increasing in its entire domain, so the maximum value is at the right endpoint of the interval.

y_{max}=y(1)=1^5-3=-2
4 0
3 years ago
you plant 15 tulip bulbs and 10 of them grow into flowers to bloom. If you plant 21 more re tulips bulbs, predict how many of th
harina [27]

Answer:

14 more flower would bloom if 21 more tulip bulb is planted.

Step-by-step explanation:

Given ratio for tulip bulbs and flowers is 15:10.

Now, finding number of flower to bloom if 21 tulip bulb are planted.

Assume if 21 tulip bulbs are planted then number of flower would bloom be"x"

ratio given: \frac{Tulip\ bulbs}{ Flower} = \frac{15}{10} = \frac{21}{x}

Cross multiplying the ratio to get:

⇒x= \frac{21\times 10}{15} = \frac{210}{15}

∴x= 14\ flowers

Hence, 14 flowers would bloom if 21 tulip bulb are planted.

If total tulip bulb is 15+21= 36, then 10+14= 24\ flowers would bloom.

5 0
3 years ago
What is P(greater than 8)?
GarryVolchara [31]

Answer:

Yes

Step-by-step explanation:

The sum must be greater than 8 it can't be 7 anyway. Sums can be 9, 10 or 12. P = (4+3+1)/36 = 3/36

3 0
1 year ago
Mr. Sanchez’s class sold fruit pies for $1.55 each and Mr. Kelly’s class sold bottles of fruit juice for $1.40 each. Together, t
Blababa [14]

Answer:

x + y = 60 and 1.55x + 1.4y = 88.20 and the solution is x = 32 and y = 28.

Mr. Sanchez’s class earned more money by $10.4.

Step-by-step explanation:

Mr. Sanchez’s class sold fruit pies for $1.55 each and Mr. Kelly’s class sold bottles of fruit juice for $1.40 each.

Let the number of sold fruit pies is x and bottles of fruit juice is y.

So, from the given condition we can write

x + y = 60 ........ (1)

⇒ 1.4x + 1.4y = 84 ....... (2) and

1.55x + 1.4y = 88.20 ........ (3)

Now, solving equations (2) and (3) we get (1.55 - 1.4)y = (88.2 - 84)

⇒ y = 28

And from equation (1) we get x = 60 - 28 = 32.

Therefore, Mr. Sanchez’s class earned more money. (Answer)

Now, this class have earned $(32 × 1.55 - 28 × 1.4) = $10.4 more. (Answer)

5 0
3 years ago
Read 2 more answers
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