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Genrish500 [490]
1 year ago
11

Two positive charge spheres, the spheres are separated by 0.40 m. The charge on the first sphere is 100 microcoulombs and the

Physics
1 answer:
agasfer [191]1 year ago
8 0

Answer: 168.75 N

Explanation:

first, let's convert microcoulombs to coulombs

q1 = 1e-4 C

q2 = 3e-5 C

r = 0.4 m

then use the equation Fe = \frac{kq_{1} q_{2}}{r^{2} }

plug in values --> F = (9e9*1e-4*3e-5)/(0.4)^2

F = 168.75 N

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A 25 kg child is riding on a swing. If the child travels 8.9 m/s at the bottom of their swing, how high into the air is the chil
Setler [38]

Answer:

h = 4.04 m

Explanation:

Given that,

Mass of a child, m = 25 kg

The speed of the child at the bottom of the swing is 8.9 m/s

We need to find the height in the air is the child is able to swing. Let the height is h. Using the conservation of energy such that,

mgh=\dfrac{1}{2}mv^2\\\\h=\dfrac{v^2}{2g}

Put all the values,

h=\dfrac{(8.9)^2}{2\times 9.8}\\\\h=4.04\ m

So, the child is able to go at a height of 4.04 m.

7 0
3 years ago
a spring is stretched 2 cm when a mass of 40 grams is hung from it what is the spring constant of the spring
Aliun [14]
F = ma = -kx
m = 0.04 kg
x = -0.02m
a = 9.81m/s²

k = ma/x = 19.6 N/m
5 0
3 years ago
Read 2 more answers
Blake has a mass of 72kg and Denise has a mass of 53kg. Blake and Denise are standing 2 meters apart on the dance floor. Denise
ivann1987 [24]

Answer:

6.36*10^-8 N

Explanation:

The magnitude of gravitational force of attraction is usually given by the formula

F = Gm1m2/r², where

F = magnitude of the force required

G = gravitational constant, 6.67*10^-11 m3 kg^-1 s^-2

m1 = mass of the first body, 72 kg

m2 = mass of the second body, 53 kg

r = radius between the bodies themselves, 2 m

Now, when we apply the formula directly, we get

F = (6.67*10^-11 * 72 * 53) / 2²

F = (6.67*10^-11 * 3816) / 4

F = 2.55*10^-7 / 4

F = 6.36*10^-8 N

8 0
3 years ago
A positive charge is moved from one point to another point along an equipotential surface. The work required to move the charge:
liberstina [14]

Answer:

b . is zero.

Explanation:

An Equipotential surface is the one that has electric potential same throughout the surface. The formula for work done in an electric field is given by

dW= qdV

Now, in an Equipotential surface dV= 0.

Hence the work done in moving a charge from one place to the other in an electric field is zero.

7 0
3 years ago
North America experienced all of the following during the last glacial period EXCEPT alpine glaciers covered the Rocky and Casca
Juli2301 [7.4K]

Answer:

the Hudson Bay was covered with alpine glaciers

Explanation:

During the last glacial period, large portions of North America were covered with ice. The majority of the ice was from the ice sheets that were covering Canada and the northern part of the United States, and the alpine glaciers on the mountain ranges. Hudson Bay was all frozen at this point of time. It was not covered with alpine glaciers though, instead it was covered with the ice of the extended ice sheets, with the ice cover reaching up to 2 km in thickness.

5 0
3 years ago
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