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Genrish500 [490]
10 months ago
11

Two positive charge spheres, the spheres are separated by 0.40 m. The charge on the first sphere is 100 microcoulombs and the

Physics
1 answer:
agasfer [191]10 months ago
8 0

Answer: 168.75 N

Explanation:

first, let's convert microcoulombs to coulombs

q1 = 1e-4 C

q2 = 3e-5 C

r = 0.4 m

then use the equation Fe = \frac{kq_{1} q_{2}}{r^{2} }

plug in values --> F = (9e9*1e-4*3e-5)/(0.4)^2

F = 168.75 N

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